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Lady_Fox [76]
3 years ago
6

(3k^3+4k^2-2)-(5k^2-9)-(7k^3+6k)

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0

Answer:

− 4 k3− k 2− 6 k+7

Step-by-step explanation:

I just simplified the expression.

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A motorist is pumping gas into his car at a rate of 5/12 of a gallon every 1/24 of a minute. At this rate, how many gallons of g
kirill115 [55]

Answer:

5 gallons

Step-by-step explanation:

We can use ratios to solve

5/12 gallon        x gallons

----------------  = -------------------

1/24 minute       1/2 minute

Using cross products

5/12 * 1/2 = x *1/24

5/24 = x/24

Multiply each side by 24

24*5/24 = x/24*24

5=x

We can pump 5 gallons

3 0
4 years ago
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You want to save for a brand-new car. You put the $5,000 your Grandma gave you when you graduated in an account that pays 6% int
Zielflug [23.3K]

Answer:

6,744.25

Step-by-step explanation:

8 0
3 years ago
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How much money has to be invested at 2.3% interest compounded continuously to have $41,000 after 17 years
k0ka [10]
We have to calculate how much money has to be invested at 2.3% interest compounded continuously to achieve $41,000 after 17 years. The formula is: A = P * ( 1 + r )^t, where A = $41,000, r = 0.023 and t = 17. 41,000 = P * ( 1 + 0.023 ) ^17; 41,000 = P * ( 1.023 )^17; 41,000 = P * 1.4719; P = 41,000 : 1.4719; P = 27,855.15. Answer: It has to be invested <span>$27,855. </span>
5 0
4 years ago
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Pls help me I think I’m wrong 10x 1/4
zmey [24]

Answer:

2.5

Step-by-step explanation:

10/1  * 1/4 = 2.5

6 0
3 years ago
WILL GIVE LOTS OF POINTS, PLEASE HELP !!!!
Dima020 [189]

Answer:

Terminal side in 2nd Quadrant

Only sin(x) & cosec(x) are positive in 2nd Quadrant

\sin( x )  =  \frac{5}{13}  \\

Perpendicular=5

Base=√(13²-5²)=√(169-25)=√144=√12²=12

Hypotenuse=13

\cos(x)= -  \frac{12}{13}  \\ \tan(x)  =  -  \frac{5}{12}  \\  \cosec(x)  =  \frac{13}{5}  \\  \sec(x)= - \frac{13}{12}  \\\cot(x) =  -  \frac{12}{5}

7 0
3 years ago
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