Answer:
1
Step-by-step explanation:
Any positive integer to power of 0 will ALWAYS be 1.
Answer:
77.5 cm
Step-by-step explanation:
15.5km* 5 cm on map/ 1 actual km= so 77.5 cm
if my answer helps please mark as brainliest.
Answer:
Step-by-step explanation:
$6/(2 DVDs) = $3/DVD, and $8/(4 CDs) = $2/CD
a DVD costs $3
a CD costs $2
Lynn bought 4 DVDs and 2 CDs for 4×$3 + 2×$2 = $16.
Pierre bought d DVDs and c CDs for $20.
d is 0, 2, 4, or 6
c = (20-3d)/2
(d,c) = (0,10), (2,7), (4,4), or (6,1)
Answer:
D. y = { -x + 2 x ≥ 1}
{ x + 1 x < 1}
Step-by-step explanation:
First is to eliminate A and C, why?
This is because of the end points shown on the graph.
As shown, if you look at the point of (2,1) it is black, this means that not only is it closed but it is also means ≤ or ≥ symbol.
You are now left with B and D
The difference between these two is the symbols; they are facing the opposite directions.
While B says x ≤ 1, and x > 1
While D says x ≥ 1, and x < 1
The direction of the symbols depends on the direction of the lines and what is part of it (some what like a shaded area)
So you answer would be D
Answer and Explanation:
A function is said to be increasing, if the derivative of function is f’(x) > 0 on each point. A function is said to be decreasing if f”(x) < 0.
Let y = v (z) be differentiable on the interval (a, b). If two points z1 and z2 belongs to the interval (a, b) such that z1 < z2, then v (z1) ≤ v (z2), the function is increasing in this interval.
Similarly, the function y = v(z) is said to be decreasing, when it is differentiable on the interval (a , b).
Two points z1 and z2 Є (a, b) such that z1 > z2, then v (z1) ≥ v(z2). The function is decreasing on this interval.
The function y = v (z)
The derivative of function Y’ = v’(z) is positive, then the function is increasing.
The function y = v (z)
The derivative of function y’ is negative, then the function is decreasing.
