In ΔIJK, the measure of ∠K=90°, the measure of ∠J=76°, and JK = 3.6 feet. Find the length of IJ to the nearest tenth of a foot.
1 answer:
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Given:
ft and
ft.
To find:
The value of P.
Solution:
We have,
Substituting and
, we get
Taking LCM, we get
Therefore, the value of P is ft.