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Lena [83]
3 years ago
5

Work out the value of 3x + 2y then x = 5 and y = 4

Mathematics
1 answer:
Sergio [31]3 years ago
5 0

the value of 3x +2y if x=5 and y=4 is 23
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What is the Domain and Range *DON'T FORGET PARENTHESES AND BRACKETS*
Alborosie

Answer:

D= {-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6}

R={-6,-5,-4,-3,-2,-1,1,2,5)

Step-by-step explanation:

5 0
3 years ago
Pls help I’ll brainlest for the right answer
Andrews [41]

Answer:

29110.87

Step-by-step explanation:

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5 0
3 years ago
Ann, Claire, and Josh collect stickers. One week, Ann collects 7 more stickers than Josh. Josh collects twice as many stickers a
UkoKoshka [18]

Answer:

Claire = 30 stickers

Josh = 60 stickers

Ann = 67 stickers

Step-by-step explanation:

Let

Claire stickers= x

Josh = 2x

Ann= 2x + 7

Total stickers = 157

Total stickers = Claire stickers + Josh stickers + Ann stickers

157 = x + (2x) + (2x+7)

157 = x + 2x + 2x + 7

157 = 5x + 7

Subtract 7 from both sides

157 - 7 = 5x + 7 - 7

150 = 5x

Divide both sides by 5

150/5 = x

30 = x

x = 30

Claire stickers= x

=30 stickers

Josh = 2x

= 2(30)

= 60 stickers

Ann= 2x + 7

= 2(30) + 7

= 60 + 7

= 67 stickers

Claire = 30 stickers

Josh = 60 stickers

Ann = 67 stickers

6 0
3 years ago
Express the terms of the following geometric sequence recursively.
BabaBlast [244]

Answer:

The most correct option for the recursive expression of the geometric sequence is;

4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2

Step-by-step explanation:

The general form for the nth term of a geometric sequence, aₙ is given as follows;

aₙ = a₁·r⁽ⁿ⁻¹⁾

Where;

a₁ = The first term

r = The common ratio

n = The number of terms

The given geometric sequence is 7, 14, 28, 56, 112

The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2

r = 2

Let, 't₁', represent the first term of the geometric sequence

Therefore, the nth term of the geometric sequence is presented as follows;

tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾

tₙ =  t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁

∴ tₙ = 2·tₙ₋₁, for n ≥ 2

Therefore, we have;

t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.

4 0
3 years ago
Write a recursive rule and an explicit rule for the<br> sequence<br> 3,7,11,15
m_a_m_a [10]

Answer:

The Recursive formula for the sequence is:

aₙ = aₙ₋₁ + d

The Explicit formula for the sequence is:

a_n=4n-1

Step-by-step explanation:

Given the sequence

3,7,11,15

Here:

a₁ = 3

computing the differences of all the adjacent terms

7 - 3 = 4, 11 - 7 = 4, 15 - 11 = 4

The difference between all the adjacent terms is the same and equal to

d = 4

We know that a recursive formula basically defines each term of a sequence using the previous term(s).

The recursive formula of the Arithmetic sequence always involves the first term.

a₁ = 3

We know that, in the Arithmetic sequence, every next term can be obtained by adding the common difference and the preceding term.

so

The recursive formula of the sequence is:

aₙ = aₙ₋₁ + d

substitute n = 2 to find the 2nd term

a₂ = a₂₋₁ + d

a₂ = a₁+ d

substitute a₁ = 3 and d = 4

a₂ = 3 + 4

a₂ = 7

Thus, the recursive formula for the sequence 3,7,11,15 is:

aₙ = aₙ₋₁ + d

<u>An explicit rule for the sequence</u>

Given the sequence

3,7,11,15

We already know that

a₁ = 3

d = 4

An arithmetic sequence has a constant difference 'd' and is defined by  

a_n=a_1+\left(n-1\right)d

substituting a₁ = 3 and d = 4

a_n=4\left(n-1\right)+3

a_n=4n-4+3

a_n=4n-1

Therefore, an explicit rule for the  sequence

a_n=4n-1

6 0
2 years ago
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