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frutty [35]
3 years ago
14

PLEASE HELP!!! i’ll give brainliest

Mathematics
1 answer:
tekilochka [14]3 years ago
8 0

Answer:

x = \sqrt{164

Step-by-step explanation:

In order to find the hypothenuse, you need to do 8^{2}  + 10^{2}. Which equals 164. Therefore, since a^{2} +b^{2} =c^{2}, a=8, b=10, and c=\sqrt{164.

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Figure PQRS is a rectangle.
il63 [147K]

Answer:

4th option.

Step-by-step explanation:

PQ is not congruent to QR, instead it is PQ is perpendicular to QR.

6 0
3 years ago
Circumference - Item 2838 Question 4 of 7
nevsk [136]
First, the formula of the circumference.

There are two formulas:
1. C = π*d
[Note: d = diameter]
2. C = 2*π*r
[Note: r = radius]
[Note: This symbol * means to multiply.]

Since we are given the diameter, it’s easier to use the first formula, π*d. Let’s not be too hard on ourselves.

Okay, so let’s state our decided formula:
C = π*d
Then replace d with the car tire’s diameter:
C = π*(32)
Afterwards, find a calculator and multiply π with 32. You will get 100.5309649 as result.

If where to round is stated in your question, round to that. If not, it’s best to round by two decimal places. In this case, we’ll round 100.5309649 to 100.53.

Please add your units as well. In this case, the final answer will be: 100.53 inches.

Since this is a word problem, don’t forget your final statement!

“The approximate circumference of the tire is 100.53 inches.”
7 0
3 years ago
Helpppppppppp WILL MARK BRAINLIST
JulsSmile [24]

Answer:

Y = 6

X = 10

Step-by-step explanation:

6 0
3 years ago
Which pair of angles are alternate interior angles?
jarptica [38.1K]
1 and 8 should be the answer I believe.
4 0
3 years ago
What type of polynomial is: 3x+x^2+4 <br>A.quadratic<br> B. quartic<br> C. linear <br>D. cubic
Svetradugi [14.3K]

Answer:

A.quadratic

Step-by-step explanation:

3x+x^2+4

Put in order from largest to smallest power of x

x^2 +3x+4

The highest power is 2

A.quadratic   highest power 2

B. quartic   highest power 4

C. linear  highest power 1

D. cubic highest power 3

3 0
2 years ago
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