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Vinil7 [7]
3 years ago
13

A system of equations has definitely many solutions. If 2y-4x=6 is one of the equations, which could be the other equation?

Mathematics
1 answer:
NISA [10]3 years ago
8 0

The given equation is ⇒⇒⇒ 2y - 4x = 6

∴ 2y = 4x + 6   ⇒ divide all the equation over 2

∴ y = 2x + 3  and it can be written as ⇒⇒⇒ y - 2x = 3

The last equation represents a straight line with a slope = 2 and y-intercept = 3

To construct a system of equations with definitely many solutions and the equation ( 2y-4x=6 ) is one of the equations, the other equation must have the same slope and the same y-intercept.

so, the general solution of the other equation is ⇒ a ( y - 2x ) = 3a

Where a is constant and belongs to R ( All real numbers )

The system of equations which has definitely many solutions is consisting of <u>Coincident lines.</u>

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Plz answer last question and im lost!
harkovskaia [24]

Answer:

\pi radian

Step-by-step explanation:

We know that angle for a full circle is 2\pi

In the given figure shape is semicircle

hence,

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thus, angle for given figure = half of  angle for a full circle = 1/2 * 2\pi = \pi

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6 0
3 years ago
Find the value of x and y.
zysi [14]

Answer:

<em>x = 9</em>

<em>y = 36</em>

Step-by-step explanation:

<u>Lines and Angles</u>

Triangle CDE is isosceles. This means the two angles of the base DE are congruent (have the same measure):

7x + 1 = 4x + 28

Subtracting 4x + 1:

3x = 27

Dividing by 3:

x = 9

Substituting in the expression for the angles:

7x + 1 = 7*9 + 1 = 64°

The angles are 64° and 64°. The other internal angle at vertex C is 180°-64°-64°=52°. This angle is congruent with its vertical angle in the triangle ABC. We are given another angle of 43°. Thus the measure of angle A is 180°-52°-43°=85°

This last angle is equal to the expression of y:

-2(3 - y) + 19 = 85

Subtracting 19:

-2(3 - y) = 66

Removing the parentheses:

-6 + 2y = 66

Adding 6:

2y = 72

Dividing by 2:

y = 36

Final answer:

x = 9

y = 36

8 0
3 years ago
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e-lub [12.9K]
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Lets take a is side of a square.
if u take parts of square from mid point and measure distance or length of any sides that would be a/2

then use Pythagorean theorem to solve hypotenuse u will get all length of small quadrilateral a/√2.same for all sides.
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