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2 years ago

11

The yogurt shop wants to mix two toppings together to create a new topping that will sell for $6 per pound. The caramel crunch c

osts $4 per pound, and pecan turtles cost $9 dollars per pound. How many pounds of each item must be mixed together to obtain 15 pounds of the new topping?

1 answer:

Mrac [35]2 years ago

5 0

The answer is 5 lbs for each item
I hope this helped! If u need me 2 break it down plz comment so and I would b happy 2 do so!

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Please answer !!!!!!!! Will mark brainliest whoever answers correctly !!!!!!!!

kirill115 [55]

Answer:

g(q) = 5/8q

Step-by-step explanation:

-7q + 12r = 3q - 4r

Add 4r to each side

-7q + 12r+4r = 3q - 4r+4r

-7q +16r = 3q

Add 7q to each side

-7q+7q +16r = 3q+7q

16r = 10q

Divide each side by 16

16r/16 = 10q/16

r = 5q/8

g(q) = 5/8q

5 0

2 years ago

At the movie theatre, child admission is $5.10 and adult admission is $9.00 .

sveticcg [70]

Answer:

$5.10 X +9.00 Y = 831.60$

We also know that for Wedneday we have two times tickets for adults compared to child so we have

$Y =2x$

And using this condition we have:

$5.10 X + 18 X = 831.60$

And solving for X we got:

$X= \frac{831.60}{23.1}=36$

So then the number of tickets sold for child are 36

Step-by-step explanation:

For this problem we can set upt the following notation

X = number of tickets for child

Y= number of tickets for adults

And we know that the total revenue for Wednesday was 831.60. So then we can set up the following equation for the total revenue

$5.10 X +9.00 Y = 831.60$

We also know that for Wedneday we have two times tickets for adults compared to child so we have

$Y =2x$

And using this condition we have:

$5.10 X + 18 X = 831.60$

And solving for X we got:

$X= \frac{831.60}{23.1}=36$

So then the number of tickets sold for child are 36

8 0

2 years ago

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

= Right hand side. (Proved)

7 0

2 years ago

What is 12 divided by 3 as an algebraic expression

butalik [34]

12/3 or the same thing as ur question but just add a division sign, eg. difference of two and one that would be 2-1

6 0

2 years ago

Who can do this? Pls help

Arte-miy333 [17]

Answer:

15. 2

16. $\frac{27}{16}$ or 1.6875

17. $\frac{17}{30}$ or 0.5666666667

18. 5

19. $\frac{35}{8}$ or 4.375

20. $\frac{22}{5}$ or 4.4

Step-by-step explanation:

Find common denominators. Multiply then simplify (if possible).

4 0

2 years ago