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baherus [9]
3 years ago
5

A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i

n stretching it from 34 to 44 cm. (Use k for the spring constant) So:W1= ? W2:=? These answers must be written in terms of k. How are W2 and W1 related? W2 = ? W1
Mathematics
1 answer:
Scilla [17]3 years ago
4 0

Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

W=\frac{1}{2}kx^2

where k= spring constant

           x= change on length of spring

Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k

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