Answer:
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum (or "no absolute maximum")
Step-by-step explanation:
There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.
The derivative is ...
h'(t) = 24t^2 -48t = 24t(t -2)
This has zeros at t=0 and t=2, so that is where extremes will be located.
We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.
h(-1) = 8(-1)²(-1-3) = -32
h(0) = 8(0)(0-3) = 0
h(2) = 8(2²)(2 -3) = -32
h(∞) = 8(∞)³ = ∞
The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.
The extrema are ...
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum
_____
Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.
The answer is -27/8= -3.375
Answer:
No.
Step-by-step explanation:
It has different order of matrices .
For <em>A</em><em>d</em><em>d</em><em>i</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>or <em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>r</em><em>a</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>, both matrices must have the same number of <u>r</u><u>o</u><u>w</u><u>s</u> and <u>c</u><u>o</u><u>l</u><u>u</u><u>m</u><u>n</u><u>s</u> .