First find the area of the whole square. Even the part that isn't part of the area. Then find the area of the spots that aren't part of the shape. Then subtract that area from the area of the whole thing.
15×18=270
(9x12)+(4×5)=128
270-128=142
Area= 142ft^2
Hi i can help you but i do not understand your question
Answer:
x = 9 ± √14
Step-by-step explanation:
x² − 18x + 67 = 0
Move the constant to the other side:
x² − 18x = -67
Take half of -18, square it, and add to both sides.
(-18/2)² = (-9)² = 81
x² − 18x + 81 = -67 + 81
x² − 18x + 81 = 14
Factor the perfect square:
(x − 9)² = 14
Solve for x:
x − 9 = ±√14
x = 9 ± √14
Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
