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3 years ago

9

Jameel drew circle A and found that the measure of the is 58°. He knows that he can use this measure to determine the measure of

many of the other angles shown in the circle. Enter the measure of ∠ADB.

1 answer:

sineoko [7]3 years ago

6 0

Answer:

pls my answer fast i need answer

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Leia cuts congruent triangular patches with an area of 45 square centimeters from a rectangular piece of fabric that is 18 centi

zimovet [89]

The number of patches that Leia can cut from 32 pieces of the fabric measuring 18 cm by 10 cm will be as follows:
Number of pieces=[total area of fabric]/[area of patch]
area of fabric=18×10=180 cm²
Area of 32 patches=180×32=5760 cm²

Area of patch=45 cm²

Number of patches=5760/45=128 patches

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3 years ago

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The admission fee at an amusement park is $1.75 for children and $4.80 for adults. On a certain day, 303 people entered the park

Nookie1986 [14]

Answer:

Children 188

Adults. 115

Step-by-step explanation:

Let the no. of children be x and adults be y

x + y = 303

x = 303 - y. .... .....(1)

1.75x + 4.80y = 881. ...........(2)

Substituting,

1.75(303-y) +4.80y = 881

530.25 -1.75y + 4.80y = 881

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3 0

3 years ago

prove that the quadrilateral whose vertices are the points A(-1,1), B(-3,4), C(1,5) and D(3,2) is a parallelogram.

Vsevolod [243]

Answer:

Since $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ , then the quadrilateral ABCD is a parallelogram.

Step-by-step explanation:

First, we label each point of the quadrilateral with the help of a graphing tool. If the quadrilateral ABCD is a parallelogram, then $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ . If we know that $A(x,y) =(-1, 1)$ , $B(x,y) =(-3,4)$ , $C(x,y) = (1,5)$ and $D(x,y) = (3,2)$ , then the measure of each vector is, respectively:

$\overrightarrow{AB} = (-3,4)-(-1,1)$

$\overrightarrow{AB} = (-2, 3)$

$\overrightarrow{DC} = (1,5)-(3,2)$

$\overrightarrow{DC} = ( -2,3)$

$\overrightarrow{AD} = (3,2)-(-1,1)$

$\overrightarrow{AD} = (4, 1)$

$\overrightarrow{BC} = (1,5)-(-3,4)$

$\overrightarrow{BC} = (4, 1)$

Since $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ , then the quadrilateral ABCD is a parallelogram.

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2 years ago