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guajiro [1.7K]
3 years ago
13

The sixth-grade class is competing in the school field day. There are 32 girls and 40 boys who want to

Mathematics
2 answers:
dsp733 years ago
6 0
8 teams
5boys
4 girls
RideAnS [48]3 years ago
5 0

Answer:

There can be 8 teams at most

4 girls on each team

5 boys on each team

hope this helps! :)

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Rules ⬆️ a dinosaur park cost $5.00 to enter plus $0.75 taxes. How much does it cost if a family of 4 went to the park
Bas_tet [7]

Answer:

23

Step-by-step explanation:

5 0
3 years ago
Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.
Andre45 [30]

Answer:

Option d)  5 to the power of negative 5 over 6 is correct.

\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}

Above equation can be written as 5 to the power of negative 5 over 6.

ie, 5^\frac{\bf -5}{\bf 6}

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}

Above equation can be written as 5 to the power of negative 5 over 6.

7 0
4 years ago
What is the exact volume of the cylinder? Cylinder with height of 6 inches and radius of 3 inches. 324π in3 18π in3 36π in3 54π
Afina-wow [57]
Volume of a cylinder is pi*r^2*h where r = radius and h = height
so 3^2*6*pi = 9*6*pi = 54pi

54 pi is the answer. mark me brainliest please!
8 0
3 years ago
Read 2 more answers
Give an example of two permutations of the same n labels 0; 1; : : : ; n ???? 1 that cannot be inorder and postorder traversal l
sertanlavr [38]
0.1 g g g. Gg g g g. Gg
8 0
3 years ago
A school dance committee has 14 volunteers. Each dance requires 3 volunteers at the door, 5 volunteers on the floor, and 6 float
siniylev [52]

There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.

Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.

We are required to find the number of ways in which the volunteers can be assigned.

Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.

nC_{r}=n!/r!(n-r)!

Number of ways in which the volunteers can be assigned is equal to the following:

Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.

Number of ways =14C_{12}

=14!/12!(14-12)!

=14!/12!*2!

=14*13/2*1

=91 ways

Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.

Learn more about combinations at brainly.com/question/11732255

#SPJ1

5 0
2 years ago
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