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Kipish [7]
3 years ago
10

A manager in your company wants to standardize all mobile device applications across different operating systems. Some users hav

e Android mobile devices, some users have iOS devices, and some users have Windows Mobile devices. How can you best answer the manager in regard to his request?
a. The manager must settle on using a single mobile operating system.
b. No apps will run on all operating systems.
c. All mobile apps will run on all mobile operating systems.
d. Some apps will work on different OS platforms, but many will not.
Computers and Technology
1 answer:
MrRissso [65]3 years ago
7 0

Answer:

The correct answer is letter "D": Some apps will work on different OS platforms, but many will not.

Explanation:

Devices using <em>Android, iOS, </em>and <em>Windows Mobile</em> Operating Systems (OS) use dedicated apps for each OS. OS providers reserve some of their key apps to the exclusive use of their devices which makes them different one from another and creates users having a bias on certain OS.  

Thus, <em>if the manager of a company is looking for standardizing all mobile applications across different OS, that is unlikely to be possible since some apps are compatible while others are not. </em>

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Natasha2012 [34]

Answer:

The answer to the given question is it will produce an "error"  

Explanation:

In the given java program it will produce an error because in java we do not use double quote("""") for message printing. We use a single quote("") for message printing. In the given program if we use a single quote(""). so it will give output that is "dogood:dogood".

The correct program to this question is can be given as:

Program:

public class Test  //define a class test.

{

   public static void main(String[] args)  //define main method

   {

       Test obj = new Test();   //create class object  

       obj.start(); //calling function

   }  

   void start()  //define function start.  

   {

       String stra = "do";   //define variable and assign value.

       String strb = method(stra);  //define variable and pass stra variable in method() function as a parameter.

       System.out.print(":"+stra + strb); //print value.  

   }

   String method(String stra)  //define function method  

   {  

       stra = stra + "good";   //add value

       System.out.print(stra);  //print value of stra

       return"good";  //return value

   }

}

Output:

dogood:dogood

6 0
3 years ago
Consider the partially-filled array named a. What does the following loop do? (cin is a Scanner object)int[] a = {1, 3, 7, 0, 0,
boyakko [2]

Answer:

Option 1: May crash at runtime because it can input more elements than the array can hold

Explanation:

Given the code as follows:

  1.        int[] a = {1, 3, 7, 0, 0, 0};
  2.        int size = 3, capacity = 6;
  3.        int value = cin.nextInt();
  4.        while (value > 0)
  5.        {
  6.            a[size] = value;
  7.            size++;
  8.            value = cin.nextInt();
  9.        }

From the code above, we know the <em>a</em> is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.

However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable <em>value</em> is always above zero, the while loop will persist.  This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.  

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Answer:

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Explanation:

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elixir [45]
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ValentinkaMS [17]

Answer:

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Explanation:

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