Answer:
A display device is the most common form of output device it presents output visually on a computer screen.the output appears temporarily on the screen and can easily altered or erased,it is sometimes referred to as softcopy
Answer:
The answer to this question as follows:
1) False
2) False
3) True
Explanation:
The description of the above option as follows
- In option 1, A single character variable must be contained in one quote mark, but it is based on the alphabet, which is a specific device, and the price of a continued character varies from one device to another, that's why it is false.
- In option 2, This option is wrong because in assembly language the identifier value must not exceed the length than 247 characters.
- In option 3, It is correct because in the variable declaration the first char should be a letter, _, @ or $letter. A total of 1-247 characters. The default case is insensitive.
Answer:
The right answer is Letter B. It is an area of memory that is used for dynamic memory allocation.
Explanation:
<em>Because a store procedure is not a computer program,neither a computer software . It is a type of code or subroutine available to applications that access a relational database management system. Such procedures are stored in the database data dictionary. It serves to save time and memory, extensive or complex processing that requires execution of several SQL. </em>
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
