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kiruha [24]
3 years ago
12

What is 5/50 as a percent

Mathematics
2 answers:
zloy xaker [14]3 years ago
8 0
All you do is 5 ÷ 50 and you get 0.1, which is 10%.
Scrat [10]3 years ago
5 0
5/50 = 10/100 = 10%

10% would be the answer.
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Answer:wow

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Use the quadratic formula s to solve 2y^2-6y-8=0
Korvikt [17]

Answer:

{4, - 1}

Step-by-step explanation:

Given

2y² - 6y - 8 = 0 ← in standard form

with a = 2, b = - 6, c = - 8

Using the quadratic formula to solve for y

y = ( - (- 6) ± \sqrt{(-6)^2-(4(2)(-8)} ) / (2 × 2)

  = ( 6 ± \sqrt{36+64} ) / 4

  = ( 6 ± \sqrt{100} ) / 4

  = ( 6 ± 10 ) / 4

x = \frac{6+10}{4} = \frac{16}{4} = 4

OR

x = \frac{6-10}{4} = \frac{-4}{4} = - 1

Solution is { 4, - 1 }

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3 years ago
Alejandro and Pedro are ring their bikes to school, after one mile they are 5/8 of the way there how much farther do they have t
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kevin and his father have collected1,456 different coinsover the years.They have a coin album that holds 30 coinson a page. If t
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Find the​ mean, variance, and standard deviation of the binomial distribution with the given values of n and p. ​, The​ mean, ​,
klemol [59]

Complete Question

Find the​ mean, variance, and standard deviation of the binomial distribution with the given values of n and p. ​, The​ mean, ​, is nothing. ​(Round to the nearest tenth as​ needed.)

    p =  0.6   n =  18

Answer:

The mean   \mu  = 10.5

The standard deviation \sigma =  2.08

The  variance   var  = 4.32

Step-by-step explanation:

From the question we are told that

      The probability of success   is  p = 0.6

      The  sample size is n = 18

  Generally given that the distribution is binomial, then the probability of failure is mathematically represented as

              q =  1- p

substituting values

              q =  1-  0.6

              q =0.4

Generally the mean is mathematically evaluated as

             \mu  =  np

substituting values

             \mu  =  18 * 0.6    

             \mu  = 10.5

The  standard deviation is evaluated as

              \sigma =  \sqrt{npq}

substituting values

               \sigma =  \sqrt{18 *  0.6 * 0.4}

              \sigma =  2.08

The variance is evaluated as

               var  =  \sigma^2

substituting value

              var  = 2.08^2

              var  = 4.32

4 0
3 years ago
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