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makvit [3.9K]
3 years ago
14

Evaluate -5-15+4+15

Mathematics
2 answers:
defon3 years ago
7 0

Answer:

-1

Step-by-step explanation:

-5-15+4+15

=-20+19

=-1

kondor19780726 [428]3 years ago
3 0

Answer:29

Step-by-step explanation:

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(f - g)(x) =  - 5 {x}^{2} +  5x  - 7

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A pole 3 m high has a shadow 5 m long when the shadow of a nearby building is 110 m long. How tall is the building? 50 m 66 m 73
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The correct answer is 66 M tall

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A rectangular box is to have a square base and a volume of 12 ft3. If the material for the base costs $0.17/ft2, the material fo
katen-ka-za [31]

Answer:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

Step-by-step explanation:

Let the dimensions of the box be x, y and z

The rectangular box has a square base.

Therefore, Volume of the boxV=x^2z

Volume of the box=12 ft^3\\

Therefore, x^2z=12\\z=\frac{12}{x^2}

The material for the base costs \$0.17/ft^2, the material for the sides costs \$0.10/ft^2, and the material for the top costs \$0.13/ft^2.

Area of the base =x^2

Cost of the Base =\$0.17x^2

Area of the sides =4xz

Cost of the sides==\$0.10(4xz)

Area of the Top =x^2

Cost of the Base =\$0.13x^2

Total Cost, C(x,z) =0.17x^2+0.13x^2+0.10(4xz)

Substituting z=\frac{12}{x^2}

C(x) =0.17x^2+0.13x^2+0.10(4x)(\frac{12}{x^2})\\C(x)=0.3x^2+\frac{4.8}{x} \\C(x)=\dfrac{0.3x^3+4.8}{x}

To minimize C(x), we solve for the derivative and obtain its critical point

C'(x)=\dfrac{0.6x^3-4.8}{x^2}\\Setting \:C'(x)=0\\0.6x^3-4.8=0\\0.6x^3=4.8\\x^3=4.8\div 0.6\\x^3=8\\x=\sqrt[3]{8}=2

Recall: z=\frac{12}{x^2}=\frac{12}{2^2}=3\\

Therefore, the dimensions that minimizes the cost of the box are:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

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3 years ago
What is the square of the imaginary number 3i?
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How is 4/16 eqaul to 0.25 plaessseeee help
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Okay! 4/16= 0.25 because  16/16 = 1 and so that means 12/16 = 0.75   and 8/16 = 0.50 and 4/16 = 0.25   Hope this helped!
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