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forsale [732]
3 years ago
9

The graph of the equation below is a circle. What is the length of the radius of the circle? (x - 4)^2 + (y + 12)^2 = 17^2

Mathematics
2 answers:
djverab [1.8K]3 years ago
8 0
The correct answer is:  [D]:  "17" .
______________________________________________________
The radius is:  " 17" .
______________________________________________________
Note:
______________________________________________________
The formula/equation for the graph of a circle is:
______________________________________________________
   (x − h)²  +<span> </span> (y − k)² =  r²  ;

in which:  

          " (h, k) " ; are the coordinate of the point of the center of the circle;

           "r" is the length of the "radius" ; for which we want to determine;
_______________________________________________________
We are given the following equation of the graph of a particular circle:
_______________________________________________________

          →  (x − 4)²  +  (y + 12)² =  17² ;

which is in the correct form:

→  " (x − h)²  +  (y − k)² =  r²  " ;

 in which:  " h = 4 " ;

                  " k = -12" ;

                   "r = 17 " ;  which is the "radius" ; which is our answer.

          →  { Note that: "k = NEGATIVE  12" } ;

→  Since the equation <u>for this particular circle</u> contains the expression:             _________________________________________________________    
                      →     "...(y + k)² ..." ;  
         
[as opposed to the standard form:  "...(y − k)² ..." ] ; 
_________________________________________________________
→  And since the coordinates of the center of a circle are represented by:
            " (h, k) " ;  
 
→  which are:  " (4, -12) " ;  (<u>for this particular circle</u>) ; 
_________________________________________________________
→  And since:  " k = -12 " ;  (<u>for this particular circle</u>) ;
_________________________________________________________
then: 

 " [y − k ] ²  =  [ y − (k) ] ²  =  " [ y − (-12) ] ² " ;
                                    
                                         =  " ( y + 12)² "  ;
                                    
{NOTE:  Since:  "subtracting a negative" is the same as "adding a positive" ;

           →   So;  " [ y − (-12 ] " = " [ y + (⁺ 12) ] " = " (y + 12) "
___________________________________________________  
Note:  The above explanation is relevant to confirm that the equation is, in fact, in "proper form"; to ensure that the:  radius, "r" ;  is:  "17" .
___________________________________________________
           →    Since:  "r  =  17 " ;  

           →  The radius is:  " 17 " ;

          which is:  Answer choice:  [D]:  "17" .
___________________________________________________
yarga [219]3 years ago
3 0
(x - 4)^2 + (y + 12)^2 = 17^2
r = 17 because radicand 289 is 17 
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ohaa [14]

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Answer:

  • scale factor: 3
  • rule: (x, y) ⇒ (3x +15, 3y -24)
  • center: (-7.5, 12)

Step-by-step explanation:

The scale factor can be found by comparing the length of CB to the length of RQ.

  B-C = (-2, 8) -(-4, 9) = (2, -1)

  Q-R = (9, 0) -(3, 3) = (6, -3)

The length of RQ is clearly 3 times the length of CB, so the scale factor (k) is ...

  ratio of corresponding differences = 6/2 = -3/-1 = 3 . . . . . scale factor

__

We know that for dilation about a point O, the distance from O is multiplied by the scale factor. For dilation of point B to point Q, this means ...

  k(B -O) = (Q -O)

Solving for Q, we get ...

  Q = kB -kO +O . . . . this is what our dilation rule will look like.

The quantity O-kO can be found by subtracting kB:

  Q -kB = O -kO = O(1 -k)

This is what we need for our dilation rule.

  Q -kB = (9, 0) -3(-2, 8) = (9+6, 0-24) = (15, -24)

So, our dilation rule is ...

  (x, y) ⇒ k(x, y) +(15, -24)

  (x, y) ⇒ (3x +15, 3y -24) . . . . . dilation rule

__

The center of dilation can be found from ...

  (Q -kB)/(1 -k) = O

  O = (15, -24)/(1 -3) = (-7.5, 12)

The center of dilation is (-7.5, 12).

_____

<em>Additional comments</em>

On the graph, the center of dilation can be found by drawing a line through a point and its image. (Points are always dilated along a line through the center of dilation.) The intersection of two such lines is the center of dilation.

On this graph, the center is just above the top edge of the chart, at point (-7.5, 12). You can see this if you carefully draw lines BQ and AP.

You usually have coordinates for two original points and two image points, so finding the scale factor the way we did is not difficult. If you just have one point on the original and the image, the scale factor is found by finding their distances from the center of dilation. Each image point is k times as far as each original point from that center.

7 0
3 years ago
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Karolina [17]

Answer:

The second answer is correct.

Step-by-step explanation:

8 0
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