The rectangle shown has a perimeter of 78 cm and the given area. Its length is 3 more than five times its width. Write and solve a system of equations to find the dimensions of the rectangle.
1 answer:
Answer:
So W is going to stand for width and L is going to stand for length.
L= 2W+6
78=2L + 2W
Those are the two equations you will use. So plug in L=2W+6 into the other one and solve.
78= 4W+12 +2W
(simplify)
78=6W+12
(-12 from both sides)
66=6W
(divide by 11)
W=11
Replug W into your equation to find L.
L=22+6
(simplify)
L=28
I hope this is right
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