Find the surface area

What is the best answer?

ratelena [41]

Add 18 to both sides to get:

px = 22

Then divide both sides by p to get:

x = 22/p

The answer is C.

7 0

3 years ago

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In a shipment of onions , 12% are damaged. 1114 onions are undamage. find the total number of onions in the shipment

katrin2010 [14]

Get on mathpapa is shows you the answer and how to explain it

3 0

3 years ago

Roger has 2 1/2 cups of butter. A recipe for a loaf of bread requires 3/4 cups of butter. How many loaves can Roger bake?

lubasha [3.4K]

The number of loaves can be determined with dividing the butter by the number of cups needed for a loaf.
loaves = 2 1/2 ÷ 3/4

Change into improper fraction
loaves = 2 1/2 ÷ 3/4
loaves = 5/2 ÷ 3/4

Change into multiplication
loaves = 5/2 ÷ 3/4
loaves = 5/2 × 4/3
loaves = 20/6
loaves = 10/3
loaves = 3.3
Because the number of loaves can't be a fraction, round it to the smaller whole number

Roger can make 3 loaves of bread

7 0

3 years ago

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Find the distance between the pair of points (-3, 1) and (2, 1)

BARSIC [14]

The answer to your question is 5

3 0

3 years ago

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A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha

8_murik_8 [283]

To model this situation, we are going to use the decay formula: $A=Pe^{rt}$
where
$A$ is the final pupolation
$P$ is the initial population
$e$ is the Euler's constant
$r$ is the decay rate
$t$ is the time in years

A. We know for our problem that the initial population is 1,250, so $P=1250$ ; we also know that after a year the population is 1000, so $A=1000$ and $t=1$ . Lets replace those values in our formula to find $r$ :
$A=Pe^{rt}$
$1000=1250e^{r}$
$e^{r}= \frac{1000}{1250}$
$e^{r}= \frac{4}{5}$
$ln(e^{r})=ln( \frac{4}{5} )$
$r=ln( \frac{4}{5} )$
$r=-02231$

Now that we have $r$ , we can write a function to model this scenario:
$A(t)=1250e^{-0.2231t}$ .

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C.
- The function is decreasing
- The function doe snot have a x-intercept
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0:
$A(0)=1250e^{(-0.2231)(0)$
$A_{0}=1250e^{0}$
$A_{0}=1250$
- Over the interval [0,10], the function will have a minimum at t=10:
$A(10)=1250e^{(-0.2231)(10)$
$A_{10}=134.28$

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: $m= \frac{A(0)-A(10)}{10-0}$
where
$m$ is the rate of change
$A(10)$ is the function evaluated at 10
$A(0)$ is the function evaluated at 0
We know from previous calculations that $A(10)=134.28$ and $A(0)=1250$ , so lets replace those values in our formula to find $m$ :
$m= \frac{134.28-1250}{10-0}$
$m= \frac{-1115.72}{10}$
$m=-111.572$
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0

3 years ago