Answer:
<u>C) They may provide selective advantages.
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<u>D) Slight differences in the genetic code may have significant results.</u>
Explanation:
The genetic code is universal, and present in most living beings . Generally, in most living organisms, the same codons are assigned to the same amino acids.
DNA sequences make up genes that may have multiple variants, called alleles. DNA deoxyribonucleic acid, is transcribed into mRNA and then translated into amino acids that form proteins.
Natural selection mainly acts on phenotypes, which are dependent on proteins and the organisms's environment. Phenotypes conferring advantageous traits are favored by the selection process- these help groups of organisms evolve over time.
Mitochondria should be the answer
Answer:
(a) 1/2; (b) no
Explanation:
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.
In contrast to this, her husband is diseased so his genotype will be XᵇY.
The Punnett square diagram related to the cross is attached.
(a) Proportion of their sons expected to be G6PD is 1/2:
They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.
(b) If the husband were G6PD deficient, the answer will not change.
The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.
Dominant m8 hope this hleps
Answer:
If an organism has a beneficial trait, they have a higher chance of survival, and if they can survive they can reproduce too.
Example: Speckled moths camouflage with the bark of trees and are not easily seen by predators. Black moths do not camouflage with the bark of trees and are easily seen by predators, therefore the black moths are eaten. Because the black moths have been eaten they cannot reproduce and pass on the trait for black wings to their offspring, but the speckled moths are able to reproduce because they survived and are able to pass on the speckled wing trait to their offspring.
