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3 years ago

How to find a gastroenterologist to review medical records?

1 answer:

5 0

Start with your primary care doctor. See who they usually refer to. Then check with your insurance to make sure they are in network with your insurance company. Most specialists require you to be referred.

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How does the circulatory system and the respiratory system work together to regulate the fish's swim bladder

PSYCHO15rus [73]

Fishes gills are engorge in blood , as water is pumped over it as the fish swims, it pulls water thru it's mouth and pushes it over it's gills extracting oxygen and the used water is ejected thru the fish slits opening that cover and protect the gill. the blood is circulated thru the fish body.

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3 years ago

You find that 21% of the population exhibits the recessive trait for eye color and the other 79%

GaryK [48]

It could be 99% or 100%

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4 years ago

2.86 A ball is dropped from rest from the top of a cliff that is 24 m high. From ground level, a second ball is thrown straight

Rashid [163]

Answer:

Distance Below the top = 6,02 m

Explanation:

To get the Final velocity of the first ball (that will be the intial velocity of the second) you need to solve the kinematic equation for Velocity:

(1) $V_{1f} =V_{1O} - gt$

As the ball is dropped from rest $V_{1O} = 0$ , so:

(2) $V_{1f} = - gt$

Note that the velocity is going to be negative as the ball is going down. To get the time it would take the ball to reach de base you can use the kinematic equation for position:

(3) $h_{1} = h_{1O} + V_{1O} *t - \frac{1}{2} gt^{2}$

We need the answer when h=0, and from the initial conditions $V_{1O} = 0, h_{1O} = 24m$ , you get:

(4) $24m = \frac{1}{2} gt_{1f}^{2}$

Solving for t, with $9,8\frac{m}{s^{2}}$ and :

(5) $t_{1f} = \sqrt{\frac{24m*2}{g} } = 2,21 s$

Replacing this time in (2), the final velocity is:

(6) $V_{1f} = -21,66 \frac{m}{s}$

So the initial velocity of ball 2 is equial to this but oppossite in direction so: $V_{2O}= -V_{1f} = 21,66 \frac{m}{s}$

The general position equation for ball 2 is (considering $h_{2O} = 0$ :

(7) $h_{2} = V_{2O} *t - \frac{1}{2} gt^{2}$

They cross paths when $h_{1}=h_{2}$ so:

(8) $h_{1O} - \frac{1}{2} gt^{2} = V_{2O} *t - \frac{1}{2} gt^{2}$

Rearranging:

(9) $t_{cross} =\frac{h_{1O}}{V_{2O} }$

Replacing values:

$t_{cross} = 1,108 s$

To get the absolute position replace $t_{cross}$ on equation (3) or (7):

$h_{cross} = 17,98 m$

To get it below the top of te cliff:

$h_{cross, from above} = 24 m - 17,98 m$

$h_{cross, from above} = 6,02 m$

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3 years ago

17. How does active transport differ from all other forms of transportation?

Vadim26 [7]

D. It must go from areas of low concentration to high, and this is only achievable with the use of energy, ATP!

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3 years ago

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A 15 mL sample of gasoline has a mass of 11 g. What is the density of the gasoline?

dybincka [34]

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3 years ago