All categories

3 years ago

Select all the correct answers.

Mathematics

1 answer:

irina1246 [14]3 years ago

6 0

Operations that can be applied to a matrix in the process of Gauss Jordan elimination are :

replacing the row with twice that row

replacing a row with the sum of that row and another row

swapping rows

Step-by-step explanation:

Gauss-Jordan Elimination is a matrix based way used to solve linear equations or to find inverse of a matrix.

The elimentary row(or column) operations that can be used are:

1. Swap any two rows(or colums)

2. Add or subtract scalar multiple of one row(column) to another row(column)

as is done in replacing a row with sum of that row and another row.

3. Multiply any row (or column) entirely by a non zero scalar as is done in replacing the row with twice the row, here scalar used = 2

You might be interested in

All statements of equality below are correct.<br> A.True<br> B.False

igor_vitrenko [27]

Answer:

Step-by-step explanation:

5 0

3 years ago

Can someone please please please help me it’s ergent

JulsSmile [24]

Answer:

D 192

Step-by-step explanation:

used: new: total

4: 1 : 5

We have 240 stamps

240/5 = 48

Multiply each number by 48

used: new: total

4*48: 1*48 : 5*48

192 : 48 : 240

There are 192 used stamps and 48 new stamps in his collections

7 0

3 years ago

Read 2 more answers

Which statement is true about milliliters and liters?

Alisiya [41]

Answer: Choice C) There are 3000 milliliters in 3 liters

mL is the abbreviation for milliliters

L is the abbreviation for liters

Since 1000 mL = 1 L, we can multiply both sides by 3 to get 3000 mL = 3 L

8 0

3 years ago

Solve each quadratic equation by completing the square. Give exact answers--no decimals.

denis-greek [22]

Answer:

$x_1 = \frac{3}{2} + \frac{1}{2}(\sqrt{47})i\\\\x_2 = \frac{3}{2} - \frac{1}{2}(\sqrt{47})i\\\\$

Step-by-step explanation:

In this problem we have the equation of the following quadratic equation and we want to solve it using the method of square completion:

$x ^ 2 -3x +14 = 0$

The steps are shown below:

For any equation of the form: $ax ^ 2 + bx + c = 0$

1. If the coefficient a is different from 1, then take a as a common factor.

In this case $a = 1$ .

Then we go directly to step 2

2. Take the coefficient b that accompanies the variable x. In this case the coefficient is -3. Then, divide by 2 and the result squared it.

We have:

$\frac{-3}{2} = -\frac{3}{2}\\\\(-\frac{3}{2}) ^ 2 = (\frac{9}{4})$

3. Add the term obtained in the previous step on both sides of equality:

$x ^ 2 -3x + (\frac{9}{4}) = -14 + (\frac{9}{4})$

4. Factor the resulting expression, and you will get:

$(x -\frac{3}{2}) ^ 2 = -(\frac{47}{4})$

Now solve the equation:

Note that the term $(x -\frac{3}{2}) ^ 2$ is always > 0 therefore it can not be equal to $-(\frac{47}{4})$

The equation has no solution in real numbers.

In the same way we can find the complex roots:

$(x -\frac{3}{2}) ^ 2 = -(\frac{47}{4})\\\\x -\frac{3}{2} = \±\sqrt{-(\frac{47}{4})}\\\\x = \frac{3}{2} \±\frac{1}{2}\sqrt{-47}\\\\x = \frac{3}{2} \±\frac{1}{2}(\sqrt{47})i\\\\x_1 = \frac{3}{2} + \frac{1}{2}(\sqrt{47})i\\\\x_2 = \frac{3}{2} - \frac{1}{2}(\sqrt{47})i\\\\$