We're looking for a solution of the form 
. By the chain rule, this solution should have total differential
and the equation is exact if the mixed second-order partial derivatives of 
are equal, i.e. 
.
The given ODE is exact, since
Then
With 
, we get
Y = x + 1
y = 2x - 1
basically we r going to sub in one y for another
x + 1 = 2x - 1
1 + 1 = 2x - x
2 = x
now we sub 2 in for x in either of the original equations to find y
y = x + 1
y = 2 + 1
y = 3
so ur solution is (2,3)
Answer: B
<u>Step-by-step explanation:</u>
x³ - 3x² + 16x - 48 = 0
→ x²(x - 3) + 16(x - 3) = 0
→ (x² + 16) (x - 3) = 0
→ (x² - (-16)) (x - 3) = 0
→ (x - 4i)(x + 4i)(x - 3) = 0
→ x - 4i = 0 x + 4i = 0 x - 3 = 0
→ x = 4i x = -4i x = 3
2 imaginary roots and 1 real root
