We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1
We need to find the integral of the function f(x) = 5x + 7 with the limits 1 and b
5/2 x^2 + 7x (limits: 1, b)
substitute the limits:
5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0
solve for b
Then after solving for b, this would be your interval input with 1: [1, b].<span />
The equivalent to that is 8.
Answer:
54.4
Step-by-step explanation:
-4(8-(-3))+7
Remove the parentheses, negative with negative will equal a positive so the new equation will be -4(8+3)+7. So 8+3=11, -4(11)+7. -4(11)=-44 and then add -44+7 which will equal -37
A I think would be the correct answer
