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Fantom [35]
3 years ago
15

Describe two factors in this expression 4{8+3x}

Mathematics
1 answer:
ioda3 years ago
5 0

A) The two factors of the expression are those expressions that are on either side of the (implied) multiplication symbol. They are ...

• 4

• (8 +3x)

B) The first factor (4) consists of one (1) term, "4".

The second factor (8 +3x) consists of two (2) terms, "8" and "3x".

C) The coefficient of x in the second factor is 3.

The coefficient of x in the overall expression is 4*3 = 12.

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Answer:

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Step-by-step explanation:

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<h2>Explanation:</h2>

We have the function:

f(x)=\frac{x^2-1}{2x+6}

The vertical asymptote can be found when the denominator equal zero, therefore:

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andrew11 [14]

we know that

the standard form of the equation of the circle is

(x-h)^{2} +(y-k)^{2}=r^{2}

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(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

x^{2} +y^{2} +8x-6y+21=0

<u>Convert to standard form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+8x) +(y^{2}-6y)=-21

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9

(x^{2}+8x+16) +(y^{2}-6y+9)=4

Rewrite as perfect squares

(x+4)^{2} +(y-3)^{2}=4

(x+4)^{2} +(y-3)^{2}=2^{2}

the center of the circle is (-4,3)

the radius of the circle is 2\ units

therefore

<u>the answer is</u>

the radius of the circle is 2\ units


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