Distance equals end minus start
(-7,-7)-(5,9)=
(-7-5,-7-9)=(-12,-16)
(-12,-16) gives us the distance point coordinates. Now to find the magnitude we can take sqrt((-12)^2+(-16)^2)=20
So the distance between the two points is 20
I hope this helps
Nope.
They don't meet the requirements of the triangle inequality.
2.1 + 4 = 6.1 < 7.9
The triangle inequality requires the sum of any two sides be greater than the third side.
Ok so let me help you with this. Here is the procedure:
<span>r² = x² + y² = 8² + 6² = 100
r = 10
x = r cosθ
y = r sinθ
sinθ = y/r = 6/10 = 3/5
</span>Hope this is what you are looking for
Answer:
13.60 See the note below.
Step-by-step explanation:
Remark
This is just the reverse of the question you just did. This time you are trying to solve for c
Givens
Solution
c^2 = a^2 + b^2 Substitute the givens.
c^2 = 8^2 + 11^2 Expand
c^2 = 64 + 121 Combine the right side by adding
c^2 = 185 Take the square root of both sides.
sqrt(c^2) = sqrt(185) Complete the operation
c = 13.601 Round to the nearest 1/100 th
c = 13.60 Note: the zero must be there or the answer does not show the nearest 1/100 th
Answer:
6.3/2.5=2.52
Step-by-step explanation:
