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galben [10]
3 years ago
13

Lola takes the train from Paris to Nice. The distance between the two cities is about 920,000 meters. If the train travels at a

speed of 230 kilometers per hour, how long will it take Lola to travel from Paris to Nice?
Mathematics
1 answer:
Vlada [557]3 years ago
5 0

First, you need to convert 920,000 meters to kilometers because the speed of the train is kilometer per hour, 920,000 meters is equal to 920 kilometers. Then, all you need to do left is take 920 (the distance from Paris to Nice in kilometer) and divide it by 230 (the speed of the train), so you will get 4. So you should write the answer like this: "The total time that took Lola to get from Paris to Nice is 4 hours."Hope this help you.


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circle a has a radius of 7 and arcs rc cs and sm are congruent to the nearest hundereth what is the length of arc rc
oksian1 [2.3K]
The complete question in the attached figure

we know that
[arcs rc +arc cs arc sm]---------------> they take up half a circle-------->180°
<span> they are all congruent
so
divide 180 by 3 ----------------> 180/3=60</span>°


Find the length of arc rc=60°<span>

if 360</span>°----------------> (2*pi*7) length of circumference 
60° -------------------> X
<span>X=60*2*pi*7/360------------> 7.327 units

the answer is
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</span>

3 0
3 years ago
The stadium has 53,000 seats seats sell for $42 in section 8 $36 in section B $30 in section C the number of seats in this in se
Zielflug [23.3K]

Answer:

Section A = 26,500 seats

Section B = 14,900 seats

Section C = 11,600 seats

Step-by-step explanation:

Total seats = 53,000

Total revenue = 1,997,400

Section A seat = $42

Section B seat = $36

Section C seat = $30

The number of seats in this in section A equals the total number of seats in section BNC

A = B + C

A + B + C = 53,000 (1)

42A + 36B + 30C = 1,997,400 (2)

Substitute A = B + C into (1)

A + B + C = 53,000

B + C + B + C = 53,000

2B + 2C = 53,000

2(B + C ) = 53,000

B + C = 53,000 / 2

= 26,500

B + C = 26,500 (3)

Substitute B + C = 26,500 into (2)

42A + 36B + 30C = 1,997,400

Recall,

A = B + C

42( 26,500) + 36B + 30C = 1,997,400

1,113,000 + 36B + 30C = 1,997,400

36B + 30C = 1,997,400 - 1,113,000

36B + 30C = 884,400. (4)

Multiply (3) by 30

B + C = 26,500 × 30

30B + 30C = 795,000 (5)

36B + 30C = 884,400 (4)

Subtract (5) from (4) to eliminate C

36B - 30B = 884,400 - 795,000

6B = 89,400

B = 89,400/6

= 14,900

B = 14,900

From (3)

B + C = 26,500

C = 26,500 - B

= 26,500 - 14,900

= 11,600

A = B + C

= 14,900 + 11,600

= 26,500

Section A = 26,500 seats

Section B = 14,900 seats

Section C = 11,600 seats

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