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3 years ago

If your car gets 35 miles per gallon, how much does it cost to drive 400 miles when gasoline costs $3.30 per gallon?

1 answer:

7 0

To solve his equation start by finding how many gallons of gas you need to purchase for the total trip.
Set up an expression that divides the total distance of the trip by the miles received per gallon.
This gives you:
400 / 35

Divide to get 11.43 gallons.

To find the cost of this, multiply the total number of gallons needed to cover the trip by the cost of each gallon.
Set this up in another expression.
This results in:
11.43 x 3.30

Multiply the values to find the total cost.
This leaves you with:
37.72

So, the total cost for gas for a 400 mile trip on 35 miles per gallon is $37.72.

I hope this is correct and helps you! :)

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What is the surface area of the prism?

svet-max [94.6K]

Answer:

base

Step-by-step explanation:

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3 years ago

I don’t know any of these lol

neonofarm [45]

In this exercise, we want to know the x-intercepts of each item. To find the x-intercepts, set y = 0 as indicated in each item and solve for x. So:

<h2>1. Answer:</h2>

B. x=-1; x=-1.75

<h3>Step by step explanation:</h3>

we have the equation:

$4x^2+11x+7=0$

We can say that this equation comes from the function $f(x)=4x^2+11x+7$ so we have set $y=0$ to find the x-intercepts. By using the quadratic formula we have:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ where: \\ \\ a=4, \ b=11, \ c=7 \\ \\ x=\frac{-11 \pm \sqrt{11^2-4(4)(7)}}{2(4)} \\ \\ x=\frac{-11 \pm \sqrt{121-112}}{8} \\ \\ \boxed{x_{1}=-1 \ and \ x_{2}=-1.75}$

<h2>2. Answer:</h2>

B. x=-1; x=-1.75

<h3>Step by step explanation:</h3>

we have the equation:

$3x^2-4x+1=0$

We can establish a function $g(x)=3x^2-4x+1$ and say that we want to find the x-intercepts of this function by setting y = 0. Therefore, by using the quadratic formula we have:

$a=3, \ b=-4, \ c=1 \\ \\ x=\frac{-(-4) \pm \sqrt{(-4)^2-4(3)(1)}}{2(3)} \\ \\ x=\frac{4 \pm \sqrt{16-12}}{6} \\ \\ \boxed{x_{1}=1 \ and \ x_{2}=\frac{1}{3}}$

<h2>3. Answer:</h2>

H. No Solution

<h3>Step by step explanation:</h3>

we have the equation:

$3x^2-4x+2=0$

We can establish a function $h(x)=3x^2-4x+2$ and say that we want to find the x-intercepts of this function by setting y = 0. Therefore, by using the quadratic formula we have:

$a=3, \ b=-4, \ c=2 \\ \\ x=\frac{-(-4) \pm \sqrt{(-4)^2-4(3)(2)}}{2(3)} \\ \\ x=\frac{4 \pm \sqrt{16-24}}{6}$

Since 16 - 24 = -8, that is, a number less than zero which is within a square root, we say that the equation $3x^2-4x+2=0$ has no any real solution.

<h2>4. Answer:</h2>

E. x=1

<h3>Step by step explanation:</h3>

we have the equation:

$x^2-2x+1=0$

We can establish a function $c(x)=x^2-2x+1$ . By setting y = 0 we'll find the x-intercepts. Let's solve this problem using other method. You can find some binomial products having a special form. So it's easier to find a solution by using distributive. The form of this polynomial is a Square of a Binomial in the form:

$(x-1)^2=0 \\ \\ Because: \\ \\ (x-1)^2=(x-1)(x-1)=x^2-x-x+1= x^2-2x+1$

Therefore, the value that satisfies this equation is $\boxed{x=1}$

<h2>5. Answer:</h2>

K. x = -1

<h3>Step by step explanation:</h3>

we have the equation:

$x^2+2x+1=0$

We can establish a function $a(x)=x^2+2x+1$ . By setting y = 0 we'll find the x-intercepts. We are going to solve this problem by using the previous method. The form of this Square of a Binomial is:

$(x+1)^2=0 \\ \\ Because: \\ \\ (x+1)^2=(x+1)(x+1)=x^2+x+x+1= x^2+2x+1$

Therefore, the value that satisfies this equation is $\boxed{x=-1}$

<h2>6. Answer:</h2>

N) x = 1/2

<h3>Step by step explanation:</h3>

we have the equation:

$4x^2-4x+1=0$

We can establish a function $b(x)=4x^2-4x+1$ and say that we want to find the x-intercepts of this function by setting y = 0. Here we will use the quadratic formula, so:

$a=4, \ b=-4, \ c=1 \\ \\ x=\frac{-(-4) \pm \sqrt{(-4)^2-4(4)(1)}}{2(4)} \\ \\ x=\frac{4 \pm \sqrt{16-16}}{8} \\ \\ \boxed{x=\frac{1}{2}}$

So we have just one solution.

<h2>7. Answer:</h2>

M) x = -1/2

<h3>Step by step explanation:</h3>

we have the equation:

$4x^2+4x+1=0$

We can establish a function $b(x)=4x^2+4x+1$ and say that we want to find the x-intercepts of this function by setting y = 0. As in the previous exercise, we will use the quadratic formula, so:

$a=4, \ b=4, \ c=1 \\ \\ x=\frac{-4 \pm \sqrt{(4)^2-4(4)(1)}}{2(4)} \\ \\ x=\frac{-4 \pm \sqrt{16-16}}{8} \\ \\ \boxed{x=-\frac{1}{2}}$

So we have just one solution.

<h2>8. Answer:</h2>

D) x = -1.45; x=1.25

<h3>Step by step explanation:</h3>

we have the equation:

$5x^2+x-9=0$

We can establish a function $D(x)=5x^2+x-9$ and say that we want to find the x-intercepts of this function by setting y = 0. By using the quadratic formula we can solve this problem, so:

$a=5, \ b=1, \ c=-9 \\ \\ x=\frac{-1 \pm \sqrt{(1)^2-4(5)(-9)}}{2(5)} \\ \\ x=\frac{-1 \pm \sqrt{1+180}}{10} \\ \\ \boxed{x_{1}=-1.45 \ and \ x_{2}=1.25}$

<h2>9. Answer:</h2>

J) x = 4; x=-3

<h3>Step by step explanation:</h3>

we have the equation:

$-x^2+x+12=0$

We can establish a function $k(x)=-(x^2-x-12)$ and say that we want to find the x-intercepts of this function by setting y = 0. In this exercise we'll use other method. Since this is a non-perfect square trinomial, we know that: