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Andre45 [30]
3 years ago
5

Simplify 5-2•3+4 A)13 B)-5 C)3 D)21

Mathematics
1 answer:
mamaluj [8]3 years ago
7 0
You will want to follow PEMDAS there is no parentheses there is also no exponents so we do multiplication first
2*3 is 6
5-6+4
There is no division skip that, we do addition first
6+4 is 10
5-10 is -5
Therefore your answer is B.-5
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A bowl of fruit punch is made by mixing 3 parts orange juice to 8 parts mango juice. How much mango juice needed to make 715 ml
Morgarella [4.7K]

Answer: 520 ml

Step-by-step explanation : Add 8+3. Then divide 11 into 715. Multiply 65 by 8.

3 0
3 years ago
In the figure above, the measure of <BDE is 20 and CD is perpendicular to DE. What is the measure of <ADC ?​
notsponge [240]

Answer:

∠ ADC = 110°

Step-by-step explanation:

∠ CDE = 90° ( angle between perpendicular lines ) , then

∠ CDB + ∠ BDE = 90°

∠ CDB + 20° = 90° ( subtract 20° from both sides )

∠ CDB = 70°

∠ ADC and ∠ CDB are adjacent angles on a straight line and sum to 180° , so

∠ ADC + ∠ CDB = 180° , that is

∠ ADC + 70° = 180° ( subtract 70° from both sides )

∠ ADC = 110°

6 0
2 years ago
Find the range and interquartile range for the data represented by the box plot.
Anarel [89]

<u>Given</u>:

Given that the data are represented by the box plot.

We need to determine the range and interquartile range.

<u>Range:</u>

The range of the data is the difference between the highest and the lowest value in the given set of data.

From the box plot, the highest value is 30 and the lowest value is 15.

Thus, the range of the data is given by

Range = Highest value - Lowest value

Range = 30 - 15 = 15

Thus, the range of the data is 15.

<u>Interquartile range:</u>

The interquartile range is the difference between the ends of the box in the box plot.

Thus, the interquartile range is given by

Interquartile range = 27 - 18 = 9

Thus, the interquartile range is 9.

3 0
3 years ago
Read 2 more answers
If p(a | b) = 0.4, p(b) = 0.8, and p(a) = 0.5, are the events a and b independent?
pashok25 [27]

The events A and B are not independent.

Given that,

                  P(A|B) = 0.4

                  P(A) = 0.5

                  P(B) = 0.8

Two events A and B are said to be independent, if P(A∩B) = P(A) P(B)

We have, P(A|B) = P(A∩B)/P(B)

Therefore, P(A∩B) = P(A|B) P(B) = 0.4 x 0.8 = 0.32

Now P(A) P(B) = 0.5 x 0.8 = 0.4

So P(A∩B) ≠ P(A)P(B)

Therefore, the events A and B are not independent.

Learn more about independent events at brainly.com/question/22881926

#SPJ4

7 0
2 years ago
Can someone please help me with 4 and 5 ???
Montano1993 [528]

Answer:

4. D  

A: -25.5=a

B: b=-4

C: c=12

D: d=8

Step-by-step explanation:

4.Between a and d they are the 2 bigger values but D was the greatest out of all of them. - divided by a - will result as a positive and 7/9=0.77 and 19/12 *I looked for the least common factor and multiplied numerator and denominator to 12 depending on the denominators value. Ex: since one of my denominators was 4, I multiply the whole fraction by 3 to get 9/12 and the other was 5/6 times 2 is 10/12 and just add 10/12 by 9/12 which is 19/12.

5.

A: All I did was multiply 8.5 and -3 and get -25.5=a.

B: I add 7 on both sides of the equation and -7 and 7 get canceled off and -11+7=-4. b=4.

C: I multiplied - to -3 and got 3, now I can subtract -3 on both sides. 15-3=12 so c=12.

D. I had to divide by 4 on both sides to get d by itself. 32/4=8 so final answer would be d=8.

5 0
3 years ago
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