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3 years ago

CAN YALL HELP PLZZzz

Mathematics

2 answers:

yulyashka [42]3 years ago

6 0

The answer would be the third one .
Perpendicular would always be the opposite of your original slope.
Hope this helps! (:

notka56 [123]3 years ago

6 0

Y - 3 = (-3/8)(x + 2)

Because,

The gradient has been inverted, showing that the line is perpendicular (indicated by the -1/m).

Additionally, slotting -2 in to that equation gives us 3, which is the y component we need (assuming that y is isolated, and made the subject, otherwise it would equal 0). This shows that this line passes through (-2, 3).

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each truck in the line weigh two tons more than the truck before it. the trucks weigh a total of 32 tons.how many pounds does a

mixer [17]

If there are 4 trucks then the first truck weighs x
then x+2tons
then x+4tons
then x+6tons = 32tons
so 4x+12=32
-12 -12
/4 /4
x=5
so plug it back in
truck 1= 5tons or 10,000lbs
truck 2= 7tons or 14,000lbs
truck 3= 9tons or 18,000lbs
<span>truck 4= 11tons or 22,000lbs</span>

6 0

3 years ago

7th grade simple solutions math 85-88

soldi70 [24.7K]

Answer:

-3 85-88 lets turn that around 88-85 is 3 but the problem is 85-88 so its -3

Step-by-step explanation:

4 0

2 years ago

Alan is 14 years old. This is twice as old as his brother James is. How old is james?

Anna007 [38]

the answer would be 7

5 0

3 years ago

which of the fallowing functions has a slope 3/2 and contains the midpoint segment between (6, 3) and (-2, 11)?

kolbaska11 [484]

Well, we know the slope is 3/2, what's the midpoint of those anyway?

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 6}}\quad ,&{{ 3}})\quad 
% (c,d)
&({{ -2}}\quad ,&{{ 11}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{-2+6}{2}~~,~~\cfrac{11+3}{2} \right)\implies (2,7)$

so, what's the equation of a line whose slope is 3/2 and runs through 2,7?

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ 2}}\quad ,&{{ 7}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{3}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-7=\cfrac{3}{2}(x-2)
\\\\\\
y-7=\cfrac{3}{2}x-3\implies y=\cfrac{3}{2}x+4$

4 0

3 years ago

Find the sum of all positive integers less than 200 that are divisible by 7.

Troyanec [42]

Step-by-step explanation:

the positive integer numbers that are divisible by 7 are an arithmetic sequence by always adding 7 :

a1 = 7

a2 = a1 + 7 = 7+7 = 14

a3 = a2 + 7 = a1 + 7 + 7 = 7 + 2×7 = 21

...

an = a1 + (n-1)×7 = 7 + (n-1)×7 = n×7

the sum of an arithmetic sequence is

n/2 × (2a1 + (n - 1)×d)

with a1 being the first term (in our case 7).

d being the common difference from term to term (in our case 7).

how many terms (what is n) do we need to add ?

we need to find n, where the sequence reaches 200.

200 = n×7

n = 200/7 = 28.57142857...

so, with n = 29 we would get a number higher than 200.

so, n=28 gives us the last number divisible by 7 that is smaller than 200 (28×7 = 196).

the sum of all positive integers below 200 that are divisible by 7 is then

28/2 × (2×7 + 27×7) = 14 × 29×7 = 2,842

6 0

2 years ago