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3 years ago

14

Danica has laid out floor tiles so they form a rectangle with a perimeter of 18 inches. what is the difference between the great

est and least possible areas of the rectangle

1 answer:

Keith_Richards [23]3 years ago

3 0

I believe this is right:
Least: 8 (length) x 1 (width) = 8
Greatest: 5 (length) x 4 (width) = 20
Difference: 20 - 8 = 12

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Find the distance between 2-4i and d 6+i

liq [111]

Answer:

7.211

Step-by-step explanation:

-For two points in the complex plane, the distance between the points is the modulus of the of the difference of the two complex numbers.

-Point 2-4i has the coordinates (2,-4)

-Point 6+i has the coordinates (6,1)

#We must find the distance between the two coordinates (2,-4) and (6,1):

$=\sqrt{(6-2)^2+(1--4)^2}\\\\=\sqrt{4^2+6^2}\\\\=\sqrt{52}\\\\=7.211$

Hence, the distance between the two points is 7.211

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2 years ago

An amusement park studied methods for decreasing the waiting time (minutes) for rides by loading and unloading riders more effic

yaroslaw [1]

Answer:49.... yep

Step-by-step explanation: 49,,,

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2 years ago

What is the sum of number 13

pychu [463]

Pretty simple, really - all you have to do us divide 509 by 14 before you're left with an answer of <span>36.35. Now, the number '36' is closer to 0 than 100, so we'll round down instead of up, therefore the number of floors to the building is 36! </span>

5 0

3 years ago

Read 2 more answers

Charlie invests £1200 at 3.5% per annum compound interest.

lbvjy [14]

Answer:

<h2>£1,330.46</h2>

Step-by-step explanation:

Using the compound interest formula $A = P(1+\frac{r}{n} )^{nt}$

A = amount compounded after n years

P = principal (amount invested)

r = rate (in %)

t = time (in years)

n = time used to compound the money

Given P = £1200., r = 3.5%, t = 3years, n = 1 year(compounded annually)

$A = 1200(1+0.035)^{3}\\ A = 1200(1.035)^{3}\\ A = 1200* 1.108717875\\A = 1,330.46$

Value of Charlie's investment after 3 years is £1,330.46

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3 years ago

Complete the following exercises by applying polynomial identities to complex numbers. Factor x2 + 64. Check your work. Factor 1

Mumz [18]

$x^2+64=x^2-(8i)^2=(x-8i)(x+8i)$

$16x^2+49=(4x)^2-(7i)^2=(4x-7i)(4x+7i)$

$(x+9i)^2=x^2+2x\cdot9i+(9i)^2=x^2+18xi+81i^2=x^2+18xi-81=x^2-81+18xi$

$(x-2i)^2=x^2-2x\cdot2i+(2i)^2=x^2-4xi+4i^2=x^2-4xi-4=x^2-4-4xi$

$(x+(3+5i))^2=x^2+2x(3+5i)+(3+5i)^2\\\\=x^2+6x+10xi+3^2+2\cdot3\cdot5i+(5i)^2\\\\=x^2+6x+10xi+9+30i+25i^2=x^2+6x+10xi+9+30i-25\\\\=x^2+6x+10xi+30i-16=x^2+6x-16+(10x+30)i$

$Used:\\i^2=-1\\\\a^2-b^2=(a-b)(a+b)\\\\(a+b)^2=a^2+2ab+b^2$

4 0

3 years ago

Read 2 more answers