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geniusboy [140]
3 years ago
5

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match the system of equations with their so

lutions

Mathematics
1 answer:
allochka39001 [22]3 years ago
5 0

Answer:

Part 1) solution {(-5,8),(3,0)} ----> y+12=x^{2}+x and x+y=3

Part 2) No solutions ----> y-15=x^{2}+4x and x-y=1

Part 3) solution [(-2,5),(3,-5)] ---> y+5=x^{2}-3x and 2x+y=1

Part 4) No solutions ---> y-6=x^{2}-3x and x+2y=2

Part 5) solution [(2,3),(8,9)] --->y-17=x^{2}-9x and -x+y=1

Part 6) solution [(-2,3),(7,-6)] --->y-15=-x^{2}+4x and x+y=1

Step-by-step explanation:

Part 1) we have

y+12=x^{2}+x ----> equation A

x+y=3 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-5,8) and (3,0)  

see the attached figure N 1

Part 2) we have

y-15=x^{2}+4x ----> equation A

x-y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs  

see the attached figure N 2

Part 3) we have

y+5=x^{2}-3x ----> equation A

2x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,5) and (3,-5)  

see the attached figure N 3

Part 4) we have

y-6=x^{2}-3x ----> equation A

x+2y=2 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs    

see the attached figure N 4

Part 5) we have

y-17=x^{2}-9x ----> equation A

-x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (2,3) and (8,9)  

see the attached figure N 5

Part 6) we have

y-15=-x^{2}+4x ----> equation A

x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,3) and (7,-6)  

see the attached figure N 6

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umka21 [38]

Hi there!

Parabola x² = 12y

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So, the co-ordinates of the focus is:-

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→ Let AB be the latus rectum of the given parabola.

→ Coordinates of end-points of latus rectum are (-2a,a), (2a,a)

→ Coordinates of A are (-6,3), while B's coordinates are (6,3).

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7 0
3 years ago
Read 2 more answers
Determine the domain of the following graph:
dedylja [7]

Answer:

Domain: -5, -3, -2, 1, 3

Step-by-step explanation:

Find all the points on the x-axis that line up with the line shown on the graph.

8 0
2 years ago
What is the value of sin 0 given that (5, -12) is a point on the terminal side of 0 ?
Roman55 [17]

Answer:

The first choice is the one you want.

Step-by-step explanation:

If we plot the point (5, -12) we will be in QIV.  Connecting the point to the origin and then drawing in an altitude to the positive x axis creates a right triangle with side adjacent to the angle being 5 units long, and the altitude being |-12|.  To find the sin of theta, we need the side opposite (got it) over the hypotenuse (don't have it).  We solve for the length of the hypotenuse using Pythagorean's Theorem:

c^2=12^2+5^2 and

c^2=169 so

c = 13.  

Now we can find the sin of the angle in the side opposite the angle over the hypotenuse:

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The first choice in your answers is the one you want.

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4 years ago
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3 years ago
Α= πω2 + 2lw<br> Solve for l
ASHA 777 [7]

Answer:

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Step-by-step explanation:

Assuming...

a = 2\pi \: w + 2lw

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