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ioda
3 years ago
7

City Community College plans to increase its enrollment capacity to keep up with an increasing number of student applicants. The

college currently has an enrollment capacity of 2200 students and plans to increase its capacity by 70 students each year. What will the enrollment capacity be 3 years from now?
Mathematics
1 answer:
aivan3 [116]3 years ago
3 0
The given above may be modeled by the arithmetic sequence with initial value (I) 2200 and common difference (d) of 70. The number of applicants every year can be written by the equation,
                          at = a1 + (n - 1) x d
From the given above, n is equal to 4. This corresponds to the term which is 3 years from now. 
                           at = 2200 + (4 - 1) x 70 = 2410
Thus, the enrollment capacity would be 2410 students. 
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is

Step-by-step explanation:

so I calculated this and I got a fraction

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7 0
3 years ago
Check my answer?
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6 0
3 years ago
Read 2 more answers
Here are the endpoints of the segments BC, FG, and JK.<br> B, −67
yulyashka [42]

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F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}

JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill

4 0
2 years ago
Can someone help, please?!
sergiy2304 [10]

Answer:

one solution

Step-by-step explanation:

4 0
3 years ago
What steps do I have to take
Ratling [72]
(x³y²)⁵
Split it for your convenience,
(x³)⁵.(y²)⁵
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So, your final answer is x¹⁵y¹⁰
6 0
3 years ago
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