Assume L=1.5W, where W=width, L= Length of the triangle.
Therefore,
Perimeter (P) = 2(W+L) = 2(W+1.5W) = 2(2.5W) = 5W=20 => W=20/5 = 4 in
Then, L=1.5W = 1.5*4 = 6 in
Area, A= L*W = 6*4 = 24 in^2
Answer:
486 mm
Step-by-step explanation:
solve each side on it's own first
First 2 rectangles: 288 mm all together
2 rectangle: 144 mm
Triangles: 54 mm
Then add rectangles and triangles:
288 mm + 144 mm + 54 mm = 486 mm
The equivalent expression for [gofoh](9) is 5(32(9)^5-1).
According to the given question.
We have three functions
f(x) = x^5 - 1
g(x) = 5x^2
h(x) = 2x
Here, we have to find the equivalent expression for [gofoh](9).
so,
gofoh(x)
= g((2x)^5 -1)
= g(32x^5 -1)
= 5(32x^5 -1)
Therefore,
gofoh(9)
= 5(32(9)^5-1)
Hence, the equivalent expression for [gofoh](9) is 5(32(9)^5-1).
Find out more information about equiavlent expression here:
brainly.com/question/28170201
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Your answer would be 91.1 units².
We can split this shape into a trapezium and a semicircle, and then find the area of both and add them.
To find the area of a trapezium, the formula is
(a + b)/2 × h, which means we do 14 (the length of AD) + 8 (the length of BC) = 22, and 22/2 = 11. Then we multiply 11 by the height of the trapezium, which is 6 because 10 - 4 = 6. This gives us the area of the trapezium as 66 units².
To find the area of a semicircle, the formula is πr²/2, and the radius is 4 because the diameter is 8 (16 - 8 = 8). This means we do π4²/2 = 16π\2 = 8π = 25.13.
Then we need to add together 66 and 25.13, which equals 91.13, or 91.1 to the nearest tenth.
I hope this helps!
