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kykrilka [37]
3 years ago
8

25 times 10*6 in normal form

Mathematics
2 answers:
emmasim [6.3K]3 years ago
8 0
ANS to 25 times 10^6

25000000
Pavlova-9 [17]3 years ago
6 0
The answer is 250000000
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The difference between a number and 12 is 20
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John, Jim and Joe each went for a medical examination. Their combined height was 5.25 m. If John was 12 cm shorter than Jim and
kolezko [41]

The 5.25 m combined height of John, Jim, and Joe, the 12 cm height difference between John and Jim and the 0.09 m difference in height between Jim and Joe, indicates that solution to the word problem is Joe was 1.73  meters tall

<h3>What is a word problem?</h3>

A word problem is a presentation of a math problem using verbal description rather than numbers, variables and operators.

The combined height of John, Jim and Joe = 5.25 m

John's height = Jim's height - 12 cm = Jim's height - 0.12

Jim's height = Joe's height + 0.09 m

Let <em>h </em>represent Joe's height, we get;

Jim's height = h + 0.09

John's height = h + 0.09 - 0.12 = h - 0.03

John's height = h - 0.03

The sum of the heights is therefore; h + h + 0.09 + h - 0.03 = 3·h + 0.06

The sum of their heights = Their combined height = 5.25 meters

Therefore; 3·h + 0.06 = 5.25

h = (5.25 - 0.06)/3 = 1.73

Joe's height, <em>h</em> = 1.73 meters

Jim's height = 1.73 + 0.09 = 1.82

Jim's height = 1.82 meters

John's height = 1.73 - 0.03 = 1.7

John's height is 1.7 meters

Joe was 1,73 meters tall

Learn more about mathematics word problems?

brainly.com/question/19386917

#SPJ1

4 0
1 year ago
On Friday it was 32 degrees at 6am and the temperature rose 3 degrees per hour for several hours. How many hours did it take the
sertanlavr [38]
At 1 pm is was 53 degrees
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3 years ago
Convert 0.6 shuttle orbits per hour to orbits per year
Hoochie [10]

Answer:

5256 orbits

Step-by-step explanation:

There are 8760 hours in a year, and at a rate of 0.6 orbits per hour you can find how many orbits there are per year by multiplying the rate and time like this

8760 x 0.6

This gives us an answer of 5256 which is the number of orbits per year

4 0
3 years ago
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