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Vlad [161]
3 years ago
11

Is - 5 a solution to the equation 6x + 5 = 5x + 8 + 2xBRAINLIEST

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
8 0
No: 6(-5) +5 = 5(-5) +8 + 2(-5)
-30 + 5 = =25 + 8 - 10
-25 ≠ -27
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Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

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3 years ago
The product of 3 and<br> increased by 5
ziro4ka [17]

Answer AND expaination

The product of a number and 3 increased by 5 is 7 less than twice the number which equation can be used to find this number , n?

its -7

the product of a number and 3: 3n

increased by 5: + 5

7 less than: - 7

twice the number: 2n

That gives us the following:

3n + 5 = 2n - 7

You only asked for the equation, not to actually help you solve for n, for note. If you do, just subtract 2n from both sides, and then subtract 5 from both sides.

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8 0
3 years ago
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