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Vlad [161]
3 years ago
11

Is - 5 a solution to the equation 6x + 5 = 5x + 8 + 2xBRAINLIEST

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
8 0
No: 6(-5) +5 = 5(-5) +8 + 2(-5)
-30 + 5 = =25 + 8 - 10
-25 ≠ -27
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Events A and B are mutually exclusive. Events B and C are non-mutually exclusive. Which Venn diagram could represent this descri
koban [17]

Answer: The 4th Venn diagram. (A and B aren't touching, A and B are touching C though.)

3 0
3 years ago
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James is kayaking. He can row 3 mph in still water. If he can travel 6 miles downstream in the same amount of time that he can t
nekit [7.7K]

Answer: the speed of the current is 0.6 mph

Step-by-step explanation:

Let x represent the speed of the current.

James is kayaking. He can row 3 mph in still water. If he can travel 6 miles downstream. Assuming he went with the current, it means that his total speed while travelling downstream is (3 + x)

Time = distance/speed

Time taken to travel downstream is

6/(3 + x)

In the same amount of time, he can travel 4 miles upstream. Assuming he went against the current, it means that his total speed while travelling downstream is (3 - x). Time taken to travel upstream is

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Since the time is the same, then

6/(3 + x) = 4/(3 - x)

Cross multiplying, it becomes

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4 0
3 years ago
4 days I have 140 copies of a book, 9 days I only have 50 left. Write an equation where c(t)=my+b where c is number of copies st
alexandr402 [8]

Answer:

c(t)=-18t+212.

Step-by-step explanation:

We have been given that 4 days I have 140 copies of a book, 9 days I only have 50 left. We are asked to write an equation c(t)=my+b, where c is number of copies still on hand and t days being available.

We have two points on line (4,140) and (9,50). Now, we will use these points to find slope as:

m=\frac{140-50}{4-9}

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y-50=-18(x-9)

y-50=-18x+162

y-50+50=-18x+162+50

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Therefore, our required equation would be c(t)=-18t+212.

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3 years ago
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Answer:

<em>your answer is D lexie will roll an even number roughly 400 times but not exactly 400 times </em>

<em>hope this helps</em>

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