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frez [133]
3 years ago
9

Factor completely q^2(p+1)+3(p+1)

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
7 0
For this case we have the following expression:
 q ^ 2 (p + 1) +3 (p + 1)
 We observe that the term that is repeated in all the members of the expression is p + 1.
 Therefore, by doing common factor we have:
 (p + 1) (q ^ 2 + 3)
 Answer:
 
The factored expression is:
 
(p + 1) (q ^ 2 + 3)
never [62]3 years ago
6 0

{q}^{2} (p + 1) +3 (p + 1) \\  = (p + 1)( {q}^{2}  + 3)
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