Ask question

Ask question

All categories

3 years ago

13

You are bored on day, so you start rolling a die. You roll it 10 times and you get a 6 eight of the times. You think this is str

ange, so you keep rolling. You roll 100 more times and only get eight more 6s, leaving a total of 16. What is the rule that accounts for this scenario?

1 answer:

Aleksandr-060686 [28]3 years ago

4 0

Step-by-step explanation:

do you that is responsible for that another is probability

You might be interested in

What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0

Tom [10]

Answer:

$x=\frac{-7-\sqrt{5}}{2}$ or $x=\frac{-7+ \sqrt{5}}{2}$

Step-by-step explanation:

The given equation is

$(2x+3)^2+8(2x+3)+11=0$

Let us treat this as a quadratic equation in $(2x+3)$ .

where $a=1,b=8,c=11$

The solution is given by the quadratic formula;

$(2x+3)=\frac{-b\pm \sqrt{b^2-4ac} }{2a}$

We substitute these values into the formula to obtain;

$(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}$

$(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}$

$(2x+3)=\frac{-8\pm \sqrt{20} }{2}$

$(2x+3)=\frac{-8\pm2\sqrt{5} }{2}$

$(2x+3)=-4\pm \sqrt{5}$

$(2x+3)=-4-\sqrt{5}$ or $(2x+3)=-4+ \sqrt{5}$

$2x=-3-4-\sqrt{5}$ or $2x=-3-4+ \sqrt{5}$

$2x=-7-\sqrt{5}$ or $2x=-7+ \sqrt{5}$

$x=\frac{-7-\sqrt{5}}{2}$ or $x=\frac{-7+ \sqrt{5}}{2}$

5 0

3 years ago

-5f-2+8-3k use f=7 and k=8

yaroslaw [1]

You have to plug in 7 for f and 8 for k making it look like -5(7)-2+8-3(8), now multiply to get the further more, -35-2+8-24, now add or subtract to get -53

Hope this helps

3 0

3 years ago

Read 2 more answers

I don’t understand how to do this question please help and explain thank you!

Karolina [17]

Here use this information and fill the table....:)

8 0

3 years ago

Read 2 more answers

Brainiest asap! please help me :)<br><br> there's 2 separate questions..

Ulleksa [173]

Answer:

1.) FI, AD, FA, DI. (Neither of them are parallel or right angles.)

2.) 95 (Same angle just upside down so it'd be the same size.)

7 0

3 years ago

Solve for m and n<br> I been stuck on this question for an hour

Crazy boy [7]

Answer:

m = 10 , n = 5 $\sqrt{2}$

Step-by-step explanation:

using the cosine and tangent ratio in the right triangle and the exact values

cos45° = $\frac{1}{\sqrt{2} }$ and tan45° = 1 , then

cos45° = $\frac{adjacent}{hypotenuse}$ = $\frac{5\sqrt{2} }{m}$ = $\frac{1}{\sqrt{2} }$ ( cross- multiply )

m = 5 $\sqrt{2}$ × $\sqrt{2}$ = 5 × 2 = 10

-----------------------------------------

tan45° = $\frac{opposite}{adjacent}$ = $\frac{n}{5\sqrt{2} }$ = 1 , then

n = 5 $\sqrt{2}$

3 0

2 years ago