Question

Find parametric equations for the line parallel to r = (6,-8) and passing through P (9, -1)

Answer 1

Answer:

$x = \frac{12-t}{4}$ and $y = \frac{t - 3}{3}$

Step-by-step explanation:

The slope of the line is:

$m = \frac{-8-0}{6-0}$

$m = -\frac{4}{3}$

The slope-intercept formula of the line is:

$y + 1 = -\frac{4}{3}\cdot (x - 9)$

$y + 1 = -\frac{4}{3}\cdot x +12$

A possible choice is:

$3\cdot y + 3 = -4 \cdot x + 12$

$t = 3\cdot y + 3 = -4\cdot x + 12$

$3\cdot y = t - 3$

$y = \frac{t - 3}{3}$

$-4\cdot x = t - 12$

$x = \frac{12-t}{4}$

The parametric equation for the line parallel to r = (6,-8) and passing through P (9, -1) is:

$x = \frac{12-t}{4}$ and $y = \frac{t - 3}{3}$