Answer:
if 1 in= 10 miles, then, 8 in= 80 miles
Step-by-step explanation:
Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
Answer:
d
Step-by-step explanation:
5.53eqbhabsfnbhjvfwj
Answer:
1
Step-by-step explanation:
cuz
Answer:I think your Answer would be x=14 but I am not sure.
Step-by-step explanation:
2log 10 (x+86)=4
Determine the defined
2log 10 (x+86)=4,x >-86
Divide both sides by 2
log 10 (x+86)=2
Solve by converting the logarithm into exponential form
x+86=10 2
Evaluate the power
x+86=100
Move constant to the right
x=100-86
Subtract the numbers
x=14,x>-86
Check if the solution is in the defined range
SOLUTION
X=14
