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3 years ago

10

When water changes from one state to another each process has a name what are the names of the processes that occur in each stat

e change.

2 answers:

Mumz [18]3 years ago

5 0

Evaporation, condensation, ice, freezing , melting

Nastasia [14]3 years ago

4 0

Ice, freezing, or melting then liquid evaporation or condensation, the vapor, deposition the ice again

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Give one source of chlorine gas

snow_lady [41]

Answer:

Sodium chloride

Sodium chloride is by a huge margin the most common chlorine compound, and it is the main source of chlorine and hydrochloric acid for the enormous chlorine-chemicals industry today.

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3 years ago

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A mixture 21.2 g of P and 79.0 g Cl2 reacts completely to form PCl3 and PCl5 as the only products. find the mass of PCl3

IRISSAK [1]

Considering the definition of reaction stoichiometry and limiting reagent, the mass of PCl₃ that could be formed is 38.26 grams.

In first place, you must know that the balanced reaction is:

4 Cl₂ + 2 P → PCl₃ + PCl₅

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cl₂: 4 moles
P: 2 moles
PCl₃: 1 mole
PCl₅: 1 mole

The molar mass of the compounds is:

Cl₂: 70.9 g/mole
P: 31 g/mole
PCl₃: 137.35 g/mole
PCl₅: 208.25 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Cl₂: 4 moles× 70.9 g/mole = 283.6 grams
P: 2 moles× 31 g/mole= 62 grams
PCl₃: 1 mole× 137.35 g/mole= 137.35 grams
PCl₅: 1mole× 208.25 g/mole= 208.25 grams

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 62 grams of P reacts with 283.6 grams of Cl₂, 21.2 grams of P reacts with how much mass of Cl₂?

$mass of Cl_{2}=\frac{21.2 grams of Px283.6 grams of Cl_{2} }{62 grams of P}$

<u><em>mass of Cl₂= 96.97 grams </em></u>

But 96.97 grams of Cl₂ are not available, 79 grams are available. Since you have less mass than you need to react with 21.2 grams of P, Cl₂ will be the limiting reagent.

Then, it is possible to determine the mass of PCl₃ produced by another rule of three, using the limiting reagent: if by stoichiometry 283.6 grams of Cl₂ produce 137.35 grams of PCl₃, 79 grams of Cl₂ how much mass of PCl₃ will be formed?

$mass of PCl_{3}=\frac{137.35 grams of PCl_{3}x79 grams of Cl_{2} }{283.6grams of Cl_{2}}$

<u><em>mass of PCl₃= 38.26 grams</em></u>

In summary, the mass of PCl₃ that could be formed is 38.26 grams.

Learn more with this examples:

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2 years ago

Green light has a frequency of 6.01 x 10^14 Hz. What is the wavelength? (Round to the nearest hundredth) *

Ivahew [28]

Answer:

4.99 x 10⁻⁷ meters or 499 nanometers

Explanation:

Use the formula:

λ = c/ν, where λ = wavelength, c = the speed of light (it's constant, 2.998 x 10⁸ m/s), and ν = frequency

λ = (2.998 x 10⁸ m/s)/(6.01 x 10¹⁴ 1/s)

λ = 4.98835 x 10⁻⁷

Round to nearest hundreth and you get 4.99 x 10⁻⁷ meters, or 499 nanometers.

7 0

3 years ago

The diagram shows an animal cell.

hjlf

Z sorry if it’s wrong good luck

3 0

3 years ago

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How many grams of calcium phosphate can be produced when 78.5 grams of calcium hydroxide reacts with excess phosphoric acid? Unb

emmainna [20.7K]

The balanced chemical equation is written as :
2H3PO4 + 3Ca(OH)2 → 6H2O + Ca3(PO4)2.
________
From the above equation we can see that 3 moles of Ca(OH)2 produces 1 mole Ca3(PO4)2 .
( Don't take tension about H3PO4 as it is present in excess )
_________
Further ,
we are given 78.5 g Ca(OH)2 .
then no of moles Ca(OH)2 given = 78.5/74 = 1.06 moles.
________
3 moles Ca(OH)2 produces → 1 mole Ca3(PO4)2.
=> 1 mole Ca(OH)2 produces → 1/3 mole Ca3(PO4)2.
=> 1.06 mole Ca(OH)2 produces → (1/3)×1.06 mole Ca3(PO4)2.
Hence number of moles Ca3(PO4)2 produced = (1/3)×1.06 = 0.353 moles.
________
Now gram molecular mass of Ca3(PO4)2 is = 310 g /mole .
hence grams of Ca3(PO4)2 produced
= 0.353× 310 = 109.43 g
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Hope it helps...

8 0

3 years ago

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