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3 years ago

10

When water changes from one state to another each process has a name what are the names of the processes that occur in each stat

e change.

2 answers:

Mumz [18]3 years ago

5 0

Evaporation, condensation, ice, freezing , melting

Nastasia [14]3 years ago

4 0

Ice, freezing, or melting then liquid evaporation or condensation, the vapor, deposition the ice again

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What are the four symbols for physical states of reactants and products?

Studentka2010 [4]

Solid -(s)
liquid - (l)
gas - (g)
aqueous - (aq)

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3 years ago

How many electron(s) is (are) needed to complete hydrogen's outer shell.

Effectus [21]

Two electrons are needed to complete hydrogen's outer shell.

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3 years ago

Magnesium metal burns in air to form a mixture of magnesium oxide (MgO, M = 40.31) and magnesium nitride (Mg3N2, M = 100.95). A

dedylja [7]

Answer:

26.95 %

Explanation:

Air contains the highest percentage of oxygen and nitrogen gases. Magnesium then combines with both of the gases:

$2 Mg (s) + O_2 (g)\rightarrow 2 MgO (s)$

$3 Mg (s) + N_2 (g)\rightarrow Mg_3N_2 (s)$

Firstly, find the total number of moles of magnesium metal:

$n_{Mg} = \frac{1.000 g}{24.305 g/mol} = 0.041144 mol$

Let's say that x mol react in the first reaction and y mol react in the second reaction. This means:

$x + y = 0.041144 mol$

According to stoichiometry, we form:

$n_{MgO} = x mol, n_{Mg_3N_2} = \frac{y}{3} mol$

Multiplying moles by the molar mass of each substance will yield mass. This means we form a total of:

$m_{MgO} = 40.31x g, m_{Mg_3N_2} = \frac{y}{3} 100.95 g =$

The total mass is given, so we have our second equation to solve:

$40.31x + 33.65y = 1.584$

We have two unknowns and two equations, we may then solve:

$x + y = 0.041144$

$40.31x + 33.65y = 1.584$

Express y from the first equation:

$y = 0.041144 - x$

Substitute into the second equation:

$40.31x + 33.65(0.04144 - x) = 1.584$

$40.31x + 1.39446 - 33.65x = 1.584$

$6.66x = 0.18954$

$x = 0.028459$

$y = 0.041144 - x = 0.012685$

Moles of nitride formed:

$n_{Mg_3N_2} = \frac{y}{3} = 0.0042282 mol$

Convert this to mass:

$m_{Mg_3N_2} = 0.0042282 mol\cdot 100.95 g/mol = 0.4268 g$

Find the percentage:

$\omega_{Mg_3N_2} = \frac{0.4268 g}{1.584 g}\cdot 100\% = 26.95 \%$

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3 years ago

The stability of atomic nuclei is most affected by the

KengaRu [80]

D. Ratio of Neutrons to Protons

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3 years ago

The half life of carbon is 5,730 years. What fraction of the original 14/6 C would be in a wooden axe handle that was 17,190 yea

Mariana [72]

Answer:

$\frac{1}{8}$

Explanation:

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

$\text{17 190 y} \times \frac {\text {1 half-life}}{\text{5730 y}} = \text{3 half-lives}$

We can construct a table.

<u>No of half-lives</u> <u>Fraction remaining</u>

1 $\frac{1}{2}$

2 $\frac{1}{4}$

3 $\frac{1}{8}$

The general formula is

$\text{Fraction remaining} = \frac{1}{2^{n}}$

where <em>n</em> = the number of half-lives.

Thus, $\frac{1}{8}$ of the original carbon remains after 17 190 y.

8 0

3 years ago