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Nana76 [90]
4 years ago
9

A 0.3480 g sample of potassium hydrogen phthalate is dissolved in 100.0 mL of water. If 32.07 mL of sodium hydroxide solution ar

e required to reach the equivalence point, what is the molarity of the sodium hydroxide solution
Chemistry
1 answer:
erma4kov [3.2K]4 years ago
4 0

Answer:

<em>Recall the following terms which is,</em>

<em> KHP is Potassium hydrogen phthalate</em>

<em>NaOH is Sodium Hydroxide </em>

<em>NaKP is molar mass</em>

<em>H20 is water</em>

Explanation:

<em>KHP + NaOH = NaKP + H2O </em>

<em>moles of KHP = 0.3480g / 204.22 g·mol−1 = .001704 </em>

<em>these will react with the same number of moles of NaOH according to the equation  </em>

<em>these are in 0.03207 L of solution </em>

<em> The  molarity of the NaOH solution = 0.001704 mol / 0.03207 L = 0.0531 M </em>

<em>the water takes no part in the reaction and the quantity can be ignored </em>

<em />

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