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inessss [21]
2 years ago
8

A student wants to increase the rate at which his powdered drink dissolves in water.

Chemistry
2 answers:
Neporo4naja [7]2 years ago
4 0

Answer:

A Increase the temperature of water

Explanation:

You can look on sciencing.com for expanation

nasty-shy [4]2 years ago
3 0
Answer, A no explanation except it makes most sense, if your reduced stirring it would decrease the rate.
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What is the mass of 4 moles of almunium atom​
lana [24]

Answer:

108 grams

Explanation:

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2 years ago
Brainliest to the best answer.
givi [52]

Answer:The heat source for our planet is the sun. Energy from the sun is transferred through space and through the earth's atmosphere to the earth's surface.

Explanation:

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2 years ago
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A first-order reaction (A → B) has a half-life of 25 minutes. If the initial concentration of A is 0.900 M, what is the concentr
Oksanka [162]

Answer:

0.6749 M is the concentration of B after 50 minutes.

Explanation:

A → B

Half life of the reaction = t_{1/2}=25 minutes

Rate constant of the reaction = k

For first order reaction, half life and half life are related by:

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{25 min}=0.02772 min^{-1}

Initial concentration of A = [A]_o=0.900 M

Final concentration of A after 50 minutes = [A]=?

t = 50 minute

[A]=[A]_o\times e^{-kt}

[A]=0.900 M\times e^{-0.02772 min^{-1}\times 50 minutes}

[A] = 0.2251 M

The concentration of A after 50 minutes = 0.2251 M

The concentration of B after 50 minutes = 0.900 M - 0.2251 M = 0.6749 M

0.6749 M is the concentration of B after 50 minutes.

7 0
3 years ago
The blank is the material that wave move through
miss Akunina [59]

Waves travel through matter, so I am 99.9% sure that is the answer.

Id look through your lesson to be sure!

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3 years ago
Un anillo, de masa 90 gramos, contiene 59,1% de oro. ¿Cuál es el valor del anillo si cada mol de oro vale S/.1800?. Considere el
LekaFEV [45]

Answer:

S/.486 es el valor del anillo

Explanation:

Para hallar el precio del anillo se deben encontrar las moles de oro que contiene este.

Si el anillo es de 90g y solo el 59.1% contiene oro, la cantidad de oro en gramos es:

90g × 59.1% = 53.19g Oro en el anillo

Ahora, para convertir los gramos de oro a moles se debe usar la masa atómica del oro (197g/mol), así:

53.19g × (1mol / 197g) = <em><u>0.27 moles de oro contiene el anillo</u></em>.

Ya que cada mol de oro cuesta S/.1800, 0.27 moles de oro (Y por lo tanto, el anillo) costarán:

0.27mol × (S/.1800 / 1mol oro) =

<h3>S/.486 es el valor del anillo</h3>
8 0
3 years ago
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