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inessss [21]
3 years ago
8

A student wants to increase the rate at which his powdered drink dissolves in water.

Chemistry
2 answers:
Neporo4naja [7]3 years ago
4 0

Answer:

A Increase the temperature of water

Explanation:

You can look on sciencing.com for expanation

nasty-shy [4]3 years ago
3 0
Answer, A no explanation except it makes most sense, if your reduced stirring it would decrease the rate.
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What happens when the density of a medium increases?
muminat
I believe it’s Refractive index
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2 years ago
The chemical formula for disulfur monoxide is:<br> A. S2O<br> B. 2SO<br> C. SO2<br> D. S2O2
Delvig [45]
The answer is (A).
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3 0
3 years ago
Which following statements is true?
Aleksandr-060686 [28]

Answer:

first one

Explanation:

hope this helps

8 0
3 years ago
Read 2 more answers
For a hydrogen- like atom, classify these electron transitions by whether they result in the absorption or emission of light:
IRISSAK [1]

When an electron transit from lower level to higher level it emits energy

When an electron transit from higher level from a lower level it absorbs energy

n=3 to n=5,  : absorption

n=1 to n=3,  : absorption

n=3 to n=2,  : emission

n=2 to n=1 : emission

the highest energy means highest wave number

wave number = Rh (1/ n1^2 - 1/n2^2)

Rh = 1.1 X 10^7 m^-1

1) n=3 to n=5

wavenumber = Rh ( 1/ 9 - 1/ 25) = 0.071 Rh

2) n=1 to n=3

wavenumber = Rh ( 1- 1/9 ) = 0.89 Rh

3) n=3 to n=2

wavenumber = Rh ( 1/4 - 1/9) = 0.139 Rh

4) n=2 to n=1

wavenumber = Rh ( 1- 1/4) = 0.75 Rh

Thus for 2) n=1 to n=3 energy will be maximum


7 0
4 years ago
Read 2 more answers
The common laboratory solvent benzene is often used to purify substances dissolved in it. The vapor pressure of benzene , C6H6,
Sidana [21]

Answer: Molecular weight of this compound is 387.3g/mol

Explanation:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

\frac{p^o-p_s}{p^o}=i\times x_2

where,

\frac{p^o-p_s}{p^o}= relative lowering in vapor pressure

i = Van'T Hoff factor = 1 (for non electrolytes)

x_2 = mole fraction of solute  =\frac{\text {moles of solute}}{\text {total moles}}

Given : 18.16 g of compound is present in 228.6 g of benzene

moles of solute = \frac{\text{Given mass}}{\text {Molar mass}}=\frac{18.16g}{Mg/mol}

moles of solvent (benzene) = \frac{\text{Given mass}}{\text {Molar mass}}=\frac{228.6g}{78g/mol}=2.93moles

x_2 = mole fraction of solute  =\frac{\frac{18.16g}{Mg/mol}}{\frac{18.16g}{Mg/mol}+2.93}

\frac{73.03-71.88}{73.03}=1\times \frac{\frac{18.16g}{Mg/mol}}{\frac{18.16g}{Mg/mol}+2.93}

M=387.3g/mol

The molecular weight of this compound is 387.3g/mol

6 0
3 years ago
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