Your two equations for this question would be:
n + d = 234
5n +10d = 16.10
So with that you must take your two equations and make them equal to eachother.
Hope this helped :)
Answer:
0.18 ; 0.1875 ; No
Step-by-step explanation:
Let:
Person making the order = P
Other person = O
Gift wrapping = w
P(p) = 0.7 ; P(O) = 0.3 ; p(w|O) = 0.60 ; P(w|P) = 0.10
What is the probability that a randomly selected order will be a gift wrapped and sent to a person other than the person making the order?
Using the relation :
P(W|O) = P(WnO) / P(O)
P(WnO) = P(W|O) * P(O)
P(WnO) = 0.60 * 0.3 = 0.18
b. What is the probability that a randomly selected order will be gift wrapped?
P(W) = P(W|O) * P(O) + P(W|P) * P(P)
P(W) = (0.60 * 0.3) + (0.1 * 0.7)
P(W) = 0.18 + 0.07
P(W) = 0.1875
c. Is gift wrapping independent of the destination of the gifts? Justify your response statistically
No.
For independent events the occurrence of A does not impact the occurrence if the other.
Answer: 
miles
Step-by-step explanation:
We can express a mixed fraction as an improper fraction.
The process is as follows:
The given mixed number = 
miles
This can be represented as
Hence, the required fraction= miles
To solve this
problem, let us analyze this step by step. The temperature for each day is as
follows:
Water temperature
on Sunday = 78 degrees F
Water temperature
on Monday = changed by -3 degrees F
Water temperature
on Tuesday = changed by 3 degrees F
We can see that
the total change of water temperature from Sunday to Tuesday is:
-3 + 3 = 0
Therefore there
is zero overall change. There the integer which represents the temperature
change is “0”.
Since the overall
change in water temperature is zero, hence the temperature on Sunday and on
Tuesday is similar.
Water temperature
on Tuesday = 78 degrees F
