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2 years ago

Subtract the sum of -11ab and -23ab from the sum of -19ab and 7ab

1 answer:

7 0

The sum of -19ab and 7ab = -19ab + 7ab = -12ab
the sum of -11ab and -23ab = -11ab + (-23ab) = - 34ab

So
<span>Subtract the sum of -11ab and -23ab from the sum of -19ab and 7ab:

</span> (-12ab) - (-34ab) = -12ab + 34ab = 22ab

Answer
22ab

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Step-by-step explanation:

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2 years ago

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2 years ago

Read 2 more answers

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

harina [27]

$L(x,y,z,\lambda)=8x+8y+4z+\lambda(4x^2+4y^2+4z^2-36)$

$L_x=8+8\lambda x=0\implies 1+\lambda x=0$
$L_y=8+8\lambda y=0\implies 1+\lambda y=0$
$L_z=4+8\lambda z=0\implies 1+2\lambda z=0$
$L_\lambda=4x^2+4y^2+4z^2-36=0\implies x^2+y^2+z^2=9$

$yL_x=y+\lambda xy=0$
$xL_y=x+\lambda xy=0$
$\implies yL_x-xL_y=y-x=0\implies y=x$

$2zL_x=2z+2\lambda xz=0$
$xL_z=x+2\lambda xz=0$
$\implies 2zL_x-xL_z=2z-x=0\implies x=2z$

$2zL_y=2z+2\lambda yz=0$
$yL_z=y+2\lambda yz=0$
$\implies 2zL_y-yL_z=2z-y=0\implies y=2z$

$x=y=2z\implies x^2+y^2+z^2=9\iff 4z^2+4z^2+z^2=9z^2=9\implies z=\pm1$

$z=\pm1\implies y=x=\pm2$

So we have two critical points, (2, 2, 1) and (-2, -2, -1), which respectively give a max of 36 and a min of -36.

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2 years ago

1 by 6 of a construction work is finished in the first year, 1 by 8 part in the second year and 1 by 12 in the third year how mu

Allisa [31]

Answer:

3/8

Step-by-step explanation:

first year's work is 1/6

second year's work is 1/8

third year's work is 1/12

combining all 3 gives us

1/6 + 1/8 + 1/12

which simplifies to 3/8

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2 years ago