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Rudik [331]
3 years ago
11

Subtract the sum of -11ab and -23ab from the sum of -19ab and 7ab

Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0
The sum of -19ab and 7ab = -19ab + 7ab = -12ab
the sum of -11ab and -23ab = -11ab + (-23ab) = - 34ab

So
<span>Subtract the sum of -11ab and -23ab from the sum of -19ab and 7ab:

</span> (-12ab) - (-34ab) = -12ab + 34ab = 22ab

Answer
22ab
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Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621​
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Answer:

The Sum Of The Integers From -6 To 58 is <u>1690.</u>

Step-by-step explanation:

Given,

a=-6

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Firstly we will find out the total number of terms that is 'n'.

Here a_1=-6\ and\ a_2=-5

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T_n=a+(n-1)d

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So there are 65 terms in between  -6 To 58.

That means we have to find the sum of 65 terms in between  -6 To 58.

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S_n=\frac{n}{2}(2a-(n-1)d)

On substituting the values, we get;

S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

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