All categories

3 years ago

I NEED YOUR HELP!! What is 2 + 3x8

Mathematics

2 answers:

Gemiola [76]3 years ago

4 0

Answer:

Don't need Help don't depend on others do you'r work by yourself why you came to this world for asking help from other not do your work by yourself.Today I am going to help but from tomorrow you have to do by yourself

Step-by-step explanation:

=2x+3x8

=add

=5x8

=x=5=8/2

=x=5/4 is your answer

vredina [299]3 years ago

3 0

Answer:

Step-by-step explanation:

$\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}$

You might be interested in

I need help please help me answer this it’s due in like 15 minutes

Svetach [21]

Answer:

If 8 Treasure Chests per 4 Hours so

12 Treasure Chests for 6 Hours

10 treasure Chests for 5 Hours

Step-by-step explanation:

If 8 Chests every 4 Hours, then 2 Chests is every 1 hour. Count up each hour, add 2 chests.

4 0

2 years ago

Yesterday between nooN And midnight the temperature dropped by 29.6 if the temperature was-5.4 at midnight what was it at noon

Deffense [45]

Answer:

24.2

Step-by-step explanation:

3 0

2 years ago

One teacher wants to give each student two and 1/6 slices of pizza if the teachers had 13 slices of pizza how many students will

hram777 [196]

Answer:

6 students.

Step-by-step explanation:

First let's combine 2 and 1/6.

6/6 + 6/6 + 1/6 = 13/6.

Now we will turn 13 to 13/1 and divide by 13/6

$\frac{13}{1} \div \frac{13}{6} = \frac{13}{1} \times \frac{6}{13}$

$\frac{13 \: \times \: 6 \: = \: 78}{ 1 \times \: 13 \: = \: 13}$

$78 \div 13 = 6$

So, the teacher will hand the pizza out to 6 students.

5 0

3 years ago

The equation 2x^2 – 8x = 5 is rewritten in the form of 2(x – p)^2 + q = 0. what is the value of q?

QveST [7]

Answer:

q = -13

Step-by-step explanation:

The given equation is:

$2x^{2}-8x=5$

Taking 2 as common from left hand side, we get:

$2(x^{2}-4x)=5\\\\2[x^{2} - 2(x)(2)]=5$

The square of difference is written as:

$(a-b)^{2}=a^2 - 2ab + b^{2}$ Equation 1

If we compare the given equation from previous step to formula in Equation 1, we note that we have square of first term(x), twice the product of 1st term(x) and second term(2) and the square of second term(2) is missing. So in order to complete the square we need to add and subtract square of 2 to right hand side. i.e.

$2[x^{2}-2(x)(2)+(2)^2-(2)^{2}]=5\\\\ 2[x^{2}-2(x)(2)+(2)^2]-2(2)^{2}=5\\\\ 2(x-2)^{2}-2(4)=5\\\\ 2(x-2)^2-8=5\\\\ 2(x-2)^{2}-8-5=0\\\\ 2(x-2)^{2}-13=0$

Comparing the above equation with the given equation:

$2(x-p)^{2}+q=0$ , we can say:

p = 2 and q= -13

6 0

3 years ago

20(base three)-11(base three) . Carry out the operation in binary system

bija089 [108]

20₃ - 11₃ = 20₃ - 10₃ - 1₃

… = 10₃ - 1₃

… = 2₃

Put another way, we "borrow a 1" from the 3¹ digits place:

20₃ = 1(3)₃ - 11₃ = 2₃

But this is just the number 2 (in base 10), which in base 2 would be 10₂.

4 0

2 years ago