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natita [175]
3 years ago
13

The tangent and secant functions are undefined for the same values true or false

Mathematics
2 answers:
Murljashka [212]3 years ago
6 0

Answer:

TRUE

Step-by-step explanation:

tanθ = 1/cotθ

cotθ = 0 when θ = ±(1/2)π, ±(3/2)π, … ±[(2n+1)/2]π.

∴ tanθ is undefined when θ = ±[(2n+1)/2]π.

secθ = 1/cosθ

cosθ = 0 when θ = ±(1/2)π, ±(3/2)π, , …, ±[(2n+1)/2]π.

∴ secθ is undefined when θ = ±[(2n+1)/2]π.

The tangent and secant functions are undefined for the same values of θ.

gizmo_the_mogwai [7]3 years ago
5 0

Answer:

True

Step-by-step explanation:

The tangent and secant functions are undefined for the same values.

Secant and tangent are trigonometry function. Each function has fix value for fix angle.

For angle 90° degree or \dfrac{\pi}{2}

As we know,

\tan90^\circ=\infty

\tan\dfrac{\pi}{2}=\infty

\sec90^\circ=\infty

\sec\dfrac{\pi}{2}=\infty

True

∞ is undefined.

Hence, Both tangent and secant are undefined at 90°

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3 0
1 year ago
Hi, umm pls help<br><br> 1/6(x-5)=1/2(x+6), solve for x <br><br> And can you please explain
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Answer:

By solving the equation \frac{1}{6}(x-5)=\frac{1}{2}(x+6) we found that   x=\frac{23}{2} \text { or }=11 \frac{1}{2}

<u>Explanation:  </u>

Given equation,

\frac{1}{6}(x-5)=\frac{1}{2}(x+6) to find x  

Step: 1 Cross multiply the denominators 2(x-5)=6(x+6)  

Step: 2 Open brackets and simplify the term 2x-10=6x+36  

Step: 3 Bring x terms on one side and simplify the equation the equation obtained is following,  

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Therefore, we solved x value from the given equation \frac{1}{6}(x-5)=\frac{1}{2}(x+6) as x=\frac{23}{2} \text { or }=11 \frac{1}{2}.

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3 years ago
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