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julsineya [31]
3 years ago
8

The sum of 3 consecutive integers is is 279. Find the integers

Mathematics
2 answers:
agasfer [191]3 years ago
6 0

Answer: 92, 93, and 94

Step-by-step explanation: The problem is asking us to find three consecutive integers that have a sum of 279. Three consecutive integers can be represented as followed.

X ⇒ <em>first integer</em>

X + 1 ⇒ <em>second integer</em>

X + 2 ⇒ <em>third integer</em>

<em />

Since the sum of our three consecutive integers is 279, we can set up an equation to represent this.

X + X + 1 + X + 2 = 279

We can simplify on the left side of the equation.

3x + 3 = 279

      -3     -3   ← subtract 3 on both sides

3x = 276

÷3     ÷3   ← divide both sides by 3

X → 92

X + 1 → 93

X + 2 → 94

Therefore, our three consecutive integers are 92, 93, and 94.

allsm [11]3 years ago
3 0

Answer:

92, 93, 94

Step-by-step explanation:

Suppose,

Three consecutive integers would be x, (x+1), (x+2)

so,

x + (x+1) +  (x+2) = 279

⇒ x+x+1+x+2= 279

⇒3x+3 = 279

subtract 3 from both sides

⇒3x = 276  

divide both sides by 3

⇒x =276/3

∴x = 92

so,

The integers are-

  • x=92
  • x+1 =92+1 =93
  • x+2 = 92+1=94

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<u>Question:</u>

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

<u>Answer:</u>

The number of real solutions for the equation x^{2}+5 x+7=0 is zero

<u>Solution:</u>

For a Quadratic Equation of form : a x^{2}+b x+c=0  ---- eqn 1

The solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  

Now , the given Quadratic Equation is x^{2}+5 x+7=0  ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} , b^2 - 4ac is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

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D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3

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