Solution (1)
for k=0 / for k=1 / for k=-1
x=0 / x=2π / x=-2π
acc / acc / rej
solution (2)
for k=0 / for k=1 / for k=-1
x=0 / x=2π/3 / x=-2π/3
acc / acc / rej
Note that i'm trying values of K which make the answer belong to our interval;
So our solution which i will represent as a set is;
S € {0,2π/3,2π}
Answer:
{36, 38, 40, 42, 44}
Step-by-step explanation:
You are implying that you are adding up 5 consecutive numbers, and should use the word "add" or the word "sum."
"The sum of 5 consecutive odd numbers is 200" leads to:
x + (x+2) + (x+4) + (x+6) + (x+8) = 200. Note how each number is 2 more than the number preceding it. In this way you can guarantee that all of the 5 numbers are odd.
Summing up, we get 5x + 20 = 200, or 5x = 180.
Dividing both sides by 5, we get x = 36.
Then the 5 consecutive integers are
{36, 38, 40, 42, 44}. These add up to 200.
Unfortunately, these are consecutive EVEN numbers, not odd numbers.
Please ensure that you have copied down this problem correctly.
The answer to the question is A
Answer:
Graph C
Step-by-step explanation:
The answer is b, since that's the only other function there that involves using absolute value
