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taurus [48]
4 years ago
10

Solve for x. (enter your answers as a comma-separated list.) matrix

Mathematics
1 answer:
Gala2k [10]4 years ago
5 0
The problem isn't provided to solve for a matrix
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the debt ratio remains the same

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AngleFBC and AngleCBG are supplements, AngleDBG and AngleDBF are supplements, and AngleCBG Is-congruent-to AngleDBF.
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3 years ago
Read 2 more answers
A particle in the first quadrant is moving along a path described by the equation LaTeX: x^2+xy+2y^2=16x 2 + x y + 2 y 2 = 16 su
ElenaW [278]

Answer:

\frac{50}{3} cm/sec.

Step-by-step explanation:

We have been given that a particle in the first quadrant is moving along a path described by the equation x^2+xy+2y^2=16 such that at the moment its x-coordinate is 2, its y-coordinate is decreasing at a rate of 10 cm/sec. We are asked to find the rate at which x-coordinate is changing at that time.

First of all, we will find the y value, when x =2 by substituting x =2 in our given equation.

2^2+2y+2y^2=16

4-16+2y+2y^2=16-16

2y^2+2y-12=0

y^2+y-6=0

y^2+3y-2y-6=0  

(y+3)(y-2)=0

(y+3)=0,(y-2)=0

y=-3,y=2

Since the particle is moving in the 1st quadrant, so the value of y will be positive that is y=2.

Now, we will find the derivative of our given equation.

2x\cdot x'+x'y+xy'+4y\cdot y'=0

We have been given that y=2, x =2 and y'=-10.

2(2)\cdot x'+(2)x'+2(-10)+4(2)\cdot (-10)=0

4\cdot x'+2x'-20-80=0

6x'-100=0

6x'-100+100=0+100

6x'=100

\frac{6x'}{6}=\frac{100}{6}

x'=\frac{50}{3}

Therefore, the x-coordinate is increasing at a rate of \frac{50}{3} cm/sec.

7 0
3 years ago
Evaluate the following expression. Be sure to show your work.
Semenov [28]

Answer:103

Step-by-step explanation:DO exponent first which is 5 to the power of 2 .And 5 to the power of 2 equals to 25.Now following pemdas,do multiplcation first.So do 25 times 4 which gives you 100.Lastly add 3 to 100 which is 103.

5 0
3 years ago
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