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3 years ago

37hrs÷5= hrs minutes

Mathematics

1 answer:

Sophie [7]3 years ago

6 0

Hi there!

$37$ hr ÷ $5$ hr $= 7.4$ min

⇒Hope this helped you!

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Factor completely 6w^4 – 54w^2

MaRussiya [10]

$6w^4-54w^2=6w^2(w^2-9)=6w^2(w^2-3^2)=6w^2(w-3)(w+3)$

4 0

3 years ago

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Find the quotient. (6x 2 + 23x + 20) ÷ (5 + 2x)

tekilochka [14]

<span>(3x -4)(2x-5) as this it is divided </span>

4 0

2 years ago

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I need help on this plZ

never [62]

Answer:

1. See the attached figure to this answer.

2. Lines A and B are parallel to each other.

3. Line Z is the transversal.

4. The same side interior angles are ∠ 4, ∠ 6 & ∠ 3, ∠ 5.

5. The alternate interior angles are ∠ 3, ∠ 6 & ∠ 4, ∠5

6. Corresponding angles are ∠ 1, ∠ 6 & ∠ 2, ∠ 5 & ∠ 3, ∠ 7 & ∠ 4, ∠ 8.

7. Alternate interior angles are ∠ 4, ∠ 5 & ∠ 3, ∠ 6 (Answer)

Step-by-step explanation:

1. See the attached figure to this answer.

2. Lines A and B are parallel to each other.

3. Line Z is the transversal.

4. The same side interior angles are ∠ 4, ∠ 6 & ∠ 3, ∠ 5.

5. The alternate interior angles are ∠ 3, ∠ 6 & ∠ 4, ∠5

6. Corresponding angles are ∠ 1, ∠ 6 & ∠ 2, ∠ 5 & ∠ 3, ∠ 7 & ∠ 4, ∠ 8.

7. Alternate interior angles are ∠ 4, ∠ 5 & ∠ 3, ∠ 6 (Answer)

7 0

2 years ago

Read 2 more answers

Clara is growing her hair out and wants it to be no longer than 15 cm but more than 11 cm. Her hair is 7 cm right now and grows

sertanlavr [38]

For this case we have the following compound inequality:
11 <7 + 0.25t ≤ 15
We must solve this inequality for time.
We have then:

For 11 <7 + 0.25t:
11 <7 + 0.25t
11 - 7 <0.25t
4 <0.25t
4 / 0.25 <t
16 <t

For 7 + 0.25t ≤ 15:
7 + 0.25t ≤ 15
0.25t ≤ 15 - 7
0.25t ≤ 8
t ≤ 8 / 0.25
t ≤ 32

Therefore, the answer is:
16 <t ≤ 32

Answer:
16 <t ≤ 32
Clara has the desired length in more than 16 weeks, but up to 32 weeks.

6 0

3 years ago

Solve the following:<br> a. 4x^2 + 5x + 3 = 2x^2 − 3x<br> b. c^2 − 14 = 5c

Jet001 [13]

Answer:

(a) x = -0.418 , -3.581

(B) c = 6.855, -1.855

Step-by-step explanation:

(A) We have given equation $4x^2+5x+3=2x^2-3x$

$2x^2+8x+3=0$

On comparing with standard quadratic equation $ax^2+bx+c$

a = 2, b = 8 and c = 3

So roots of the equation will be $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-8\pm \sqrt{8^2-4\times 2\times 3}}{2\times 2}=\frac{-8\pm 6.324}{4}=-0.418,-3.581$

(b) $c^2-14=5c$

$c^2-5c-14=0$

a = 1, b = -5 and c= -14

So $c=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-(-5)\pm \sqrt{(-5)^2-4\times 1\times (-14)}}{2\times 1}=\frac{5\pm 8.71}{2}=6.855,-1.855$

7 0

3 years ago

37hrs÷5= hrs minutes​

37hrs÷5= hrs minutes